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Natasha2012 [34]
3 years ago
8

I'm appreciate if anyone can help me to do this question .. Question 5.. Thank you.

Mathematics
2 answers:
inn [45]3 years ago
7 0
The value of u is 5. 1/10 = 1/5 + 1/15 = 2/20 which equals 1/10
son4ous [18]3 years ago
5 0

u = 30

continuing your method

\frac{1}{10} = \frac{1}{u} + \frac{1}{15}

subtract \frac{1}{15} from both sides

\frac{1}{u} = \frac{1}{10} - \frac{1}{15} thus

\frac{1}{u} = \frac{3}{30} - \frac{2}{30}

\frac{1}{u} = \frac{1}{30} ⇒ u = 30



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6 0
2 years ago
F(x)=-x^2+8x+15 ...?
rusak2 [61]
Here i how I would do it:<span>f(x)=−<span>x2</span>+8x+15</span>
set f(x) = 0 to find the points at which the graph crosses the x-axis. So<span>−<span>x2</span>+8x+15=0</span>
multiply through by -1<span><span>x2</span>−8x−15=0</span> <span>(x−4<span>)2</span>−31=0</span> <span>x=4±<span>31<span>−−</span>√</span></span>
So these are the points at which the graph crosses the x-axis. To find the point where it crosses the y-axis, set x=0 in your original equation to get 15. Now because of the negative on the x^2, your graph will be an upside down parabola, going through<span>(0,15),(4−<span>31<span>−−</span>√</span>,0)and(4+<span>31<span>−−</span>√</span>,0)</span>
To find the coordinates of the maximum (it is maximum) of the graph, you take a look at the completed square method above. Since we multiplied through by -1, we need to multiply through by it again to get:<span>f(x)=31−(x−4<span>)2</span></span><span>
Now this is maximal when x=4, because x=4 causes -(x-4)^2 to vanish. So the coordinates of the maximum are (4,y). To find the y, simply substitute x=4 into the equation f(x) to give y = 31. So it agrees with the mighty Satellite: (4,31) is the vertex.</span>
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3 years ago
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