Answer:
Equation of given circle :- x² + y² = 4
Step-by-step explanation:
The equation of the circle with center (0, 0) and radius r is given by,
x² + y² = r²
It is given that, a circle with center (0,0) and (-1,-3) a point on the circle
To find the radius of circle
radius r = √[(0 - - 1)² + (0 - -3)²] =√(1 + 3) =√4 = ±2
r = 2
<u>To find the equation of circle</u>
x² + y² = r²
x² + y² = 2²
x² + y² = 4
Step-by-step explanation:
- step 2
3)The original rational number was 17/12.
4)The age of Ruby and Reshma are 20 and 28 years respectively.
Explanation:
3)Let the numerator be x.
So denominator will be (x - 5)
If we add 5 to numberator then it will be (x + 5)
New number is (x + 5)/(x - 5)=11/6
Solve for X by cross multiplying
6(x + 5)=11(x - 5)
6x + 30=11x - 55
5x=85
x=17
So original rational number was 17/12.
4)The ages of Ruby and Reshma are in the ratio 5:7
So, let the present ages of Ruby and Reshma be 5x and 7x respectively.
Also, it is given that four years from now the ratio of their ages will be 3:4
So, the equation - 5x + 4 / 7x + 3 = 3/4
⇒4(5x+4)=3(7x+4)
⇒20x+16=21x+12
⇒21x−20x=16−12
⇒x=4
⇒5x=20 and 7x=28
The age of Ruby and Reshma are 20 and 28 years respectively.
Answer:10 over 13 x
Step-by-step explanation: convert the decimal number into a fraction 800-5x divided by 13 over 2
to divided by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13
factor out 5 from the expression 5(160-x x2over 13) use the commutative property to reorder the terms 5(160-2over 13x) factor out 1 over 13 from the expression 5x 1 over 13x(2080-2x)factor out 2 from the expression 5x 1 over13 x2(1040-x)use the commutative property to recorder the terms 5*2x 1 over 13x (1040x) calculate the product 10 over 13x(1040-x) solution 10 over 13x (1040-x)
for simplify expression: covert the decimal number into a fraction 800-5x divided by 13 over 2 to divide by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13 calculate the product 800- 10 over 13x
solution: 800-10 over 13x so your answer would still be
