Start with the equation of a circle whose center is at (h,k) and whose radius is r:
(x-h)^2 + (y-k)^2 = r^2
Substituting the given coordinates of the center:
(x-5)^2 + (y-[-5])^2 = r^2, or (x-5)^2 + (y+5)^2 = r^2
Substituding the given coordinates of a point (6,-2) on the circle:
(6-5)^2 + (-2+5)^2 = r^2
Simplifying:
1^2 + 3^2 = r^2, or 1 + 9 = r^2, or 10= r^2. Then r = sqrt(10).
The answer should be 6 units. -1 > 0 > 1 > 2 > 3 > 4 > 5 : 6 units
Answer:
You would figure this out by the method of substitution
Step-by-step explanation:
a= -3/2
b= 5/4
c=7/8
a(b+c) = a(b)+a(c)
Substitute
-3/2(5/4 +7/8) = -3/2(5/4)+-3/2(7/8)
-51/16 =-51/16
Explecit formula
hmm, seems to be a geometric sequence
so
an=a1+d(n-1)
d=common differnce
a1=first term
given
a1=firstterm=9.2
and the difference between each tierm is 1.8
an=9.1-1.8(n-1) is da equation
so 4th option
