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4 years ago

Need help with the answer

Mathematics

1 answer:

kozerog [31]4 years ago

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6/10, 0.6 hit the thanks button and 5 stars plz thankyou!!!!

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Part two of Two Variable Statistics<br> Scatter Plots and Function Models

Citrus2011 [14]

Answer:

for part B im not really sure

for part C the answer should be C

for part D the estimate population should be 6 million

for part E tge answer should be between 2025 to 2030

6 0

4 years ago

Solve for t.......<br><img src="https://tex.z-dn.net/?f=4%20%28t%20%2B%20%5Ccfrac%7B1%7D%7B4%7D%20%5C%3A%20%20%29%20%3D%203" id=

Bingel [31]

Answer:

$t = \cfrac{1}{2}$

Step-by-step explanation:

Given equation:

$4(t+\cfrac{1}{4})=3$

Divide both sides by 4:

$t+\cfrac{1}{4}=\cfrac{3}{4}$

Subtract 1/4 from both sides:

$t = \cfrac{3}{4}- \cfrac{1}{4}$

$t = \cfrac{2}{4}$

Simplify:

$t = \cfrac{1}{2}$

7 0

2 years ago

Read 2 more answers

What is y in the equation 2/3 (2y+1) = 3/7 (2-y)

Alik [6]

Answer:

$y=\frac{4}{37}$

Step-by-step explanation:

$\frac{2}{3}(2y+1)=\frac{3}{7}(2-y)$

$\frac{4}{3}y+\frac{2}{3} =\frac{6}{7}- \frac{3}{7}y$

Add $\frac{3}{7}y$ on both sides and subtract $\frac{2}{3}$ on both sides.

$(\frac{3}{7}y- \frac{2}{3})+\frac{4}{3}y+\frac{2}{3} =\frac{6}{7}- \frac{3}{7}y+(\frac{3}{7}y- \frac{2}{3})$

$\frac{3}{7}y+\frac{4}{3}y=\frac{6}{7}-\frac{2}{3}$

Solve the fractions.

$\frac{(3)(3)+(7)(4)}{(7)(3)}y=\frac{(6)(3)-(7)(2)}{(7)(3)}$

$\frac{9+28}{21} y=\frac{18-14}{21}$

$\frac{37}{21}y =\frac{4}{21}$

Multiply by the reciprocal of the fraction with the variable to isolate the variable. The reciprocal is the inverted fraction.

$\frac{21}{37}*\frac{37}{21}y =\frac{4}{21}*\frac{21}{37}$

$y=\frac{4}{37}$

4 0

4 years ago

Read 2 more answers

arthur wants to buy an item that costs p dollars before tax. using a 6% sales tax rate, write two different expressions that rep

Mkey [24]

For this case we have the following variable:

p: cost of the item that Arthur wants to buy before tax

The expression for the 6% tax is given by:

$\frac{6}{100} p$

Or equivalently:

$0.06p$

Therefore, two different expressions for the total cost are:

Expression 1:

$p + \frac{6}{100} p$

Expression 2:

$p + 0.06p$

To prove that they are equal, suppose that the item costs $ 100:

Expression 1:

$p + \frac{6}{100} p$

$100+ \frac{6}{100} 100$

$100 + 6$

$106$

Expression 2:

$p + 0.06p$

$100 + 0.06 (100)$

$100 + 6$

$106$

Since the cost is the same, then the expressions are the same.

Answer:

Two different expressions that model the problem are:

$p + \frac{6}{100} p$

$p + 0.06p$

8 0

3 years ago

The data set represents the total number of tickets each person purchased for a play.

ozzi

Answer

1.5

Solution

The median is the middle number

8 0

3 years ago