Answer:

Step-by-step explanation:
If the population increases at a rate of 4% per annum, then:
In year 1:

Where
is the initial population and
is the population in year n
In year 2

It can also be written as:

Taking out common factor

Taking out common factor (1 + 0.04)

Taking out again common factor 
Simplifying

So

This is the equation that represents the population for year n
Then, in 4 years, the population will be:

Answer:
V ≈ 527.79
Step-by-step explanation:
Formula is V= πr2h
therefore
V = π * 4 * 2 * 10.5
V = π * 8 * 10.5
V ≈ 527.79
You're really just finding the volume of the cargo-carry part.
V= L x W x H
V= 8.3m x 3m x 4.2m
V= 104.58 m3 or 105 m3 (rounded)
ANSWER: The maximum volume of sand Billy's truck can carry is about 105 m3.
I believe the answer is 4