Answer:
14
Step-by-step explanation:
Answer:
- high tide occurs at 12 noon and 12 midnight
- Low tide occurs at 6 a.m and 6 p.m
- maximum depth value = 20 ft
- Minimum depth value = 15 ft
Step-by-step explanation:
The depth is modelled as;
y = 20 + 5 cos (πt/6)
We are told that t = 0 represents 12:00 midnight.
This is high tide because at t = 0, the cos function will be at it's maximum value of 1 since cos 0 = 1.
Max depth value is;
y = 20 + 5(0)
y = 20 ft
Minimum depth value will be the low tide and it will be when the cos function is equal to -1.
Thus;
y = 20 + 5(-1)
y = 15 ft
Since t represents number of hours and since at 12 midnight, t = 0, thus; high tide will occur again at;
12 noon
Also, let's check for low tide.
Let's try t = 6 which means 6 a.m
Thus;
y = 20 + 5 cos (π(6)/6)
y = 20 + 5 cos π
Cos π has a value of -1
Thus;
y = 20 + 5(-1)
y = 20 - 5
y = 15 ft
Thus;
Low tide occurs at 6 a.m and 6 p.m
Answer: Its the first one
Explanation:Yes because it is trust me yes
Answer:
c² - 63
Step-by-step explanation:
4c - 10 = 30
3c ÷ 3 = 10
c² - 63 = 37
c² ÷ 10 = 10
Since c² - 63 = 37 and c + 25 = 35, 37 is greater than 35 so it would make sense to choose c² - 63 as the answer.
c + 25 < 37
I hope this helps you :D
Easy!
Wouldn’t it just be
(With your formula of volume/rate=time)
250mL/2 hours=
125mL a hour
2.083(three is repeated)mL a minute
0.03472(two is repeated)mL a second
At least that’s what I think
