Answer:
x = -1 and y = -1
Step-by-step explanation:
to solve this equation we say
let
2x-5y=3.......................................... equation 1
4y-x=-3............................................equation 2
from equation 2
4y-x=-3............................................equation 2
4y + 3 = x
i.e
x = 4y + 3 ............................................. equation 3
put x = 4y + 3 in equation 1
2(4y +3) - 5y = 3
8y + 6 -5y = 3
3y +6 = 3
3y= 3-6
3y -3
divide both sides by the coefficient of y which is 3
3y/3 = -3/3
y = -1
put y = -1 into equation 3
x = 4y + 3 ............................................. equation 3
x = 4(-1) + 3
x = -4 + 3
x = -1
therefore the value of x = -1 and y = -1 respectively
A) 4a - 3b + 2c
4(2, -1, 5) - 3(4, 3 , -2) + 2(5, 4, 0) = (8, -4, 20) - (12, 9, - 6) + (10, 8, 0) =
= (8 - 12 + 10 , -4 - 9 + 8 , 20 + 6 + 0) = (6, - 5, 26)
Answer: (6, - 5, 26)
b) magnitude of vector b
![\sqrt{4^2+3^2+(-2)^2} = \sqrt{16+9+4} = \sqrt{29} ~ 5.4](https://tex.z-dn.net/?f=%20%5Csqrt%7B4%5E2%2B3%5E2%2B%28-2%29%5E2%7D%20%3D%20%5Csqrt%7B16%2B9%2B4%7D%20%3D%20%5Csqrt%7B29%7D%20~%205.4)
c) vector of length 7 parallel to vector c
=> m(5,4,0) = (5m,4m,0)
=>
![\sqrt{(5m)^2+(4m)^2+0}= \sqrt{25m^2+16m^2}= \sqrt{41m^2}=m \sqrt{41}=7](https://tex.z-dn.net/?f=%20%5Csqrt%7B%285m%29%5E2%2B%284m%29%5E2%2B0%7D%3D%20%5Csqrt%7B25m%5E2%2B16m%5E2%7D%3D%20%5Csqrt%7B41m%5E2%7D%3Dm%20%5Csqrt%7B41%7D%3D7%20%20%20%20)
=> m = 7 / √41 ≈ 1.093
=> 1.093 (5, 4, 0) = (5.465 , 4.372, 0)
Answer: (5.465 , 4.372 , 0)
Plug the 5 into the x in the equation 2x. it should be 2(5) which equals 10.
I do not know the decimal, but I know the ratio. 7/50. I am not positive about my answer as a decimal but I think it is 7.50.
Answer:
Step-by-step explanation:
150n to the right