An=a*q^(n-1)
a7=a*q^6
a7=4096*(1/2)^6=4096/32=128
Let's assume we were given 2 numbers: 15 and 30. Their sum is:

We want to express it as the product of GCF and another sum.
15 is divisible by: 1, 3, 5, 15
30 is divisible by: 1, 2, 3, 5, 6, 10, 15, 30
The greatest number that appears in 2 series is 15.


In this case sum of two numbers can always be written as:
116/21 hope this helped !
Answer:
A
hope this helps
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Step-by-step explanation:
Answer: this is the answer to your question look at the picture
Step-by-step explanation: