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iVinArrow [24]
3 years ago
8

A cruise left port A and traveled towards port B 225 km away. After 1.5 hours of travel, the cruise was stopped for a half an ho

ur and then it had to increase its speed by 10 km/hour in order to reach port B on time. Find the original speed of the cruise.

Mathematics
1 answer:
Softa [21]3 years ago
7 0

Answer:

50

Step-by-step explanation:

v = the original speed of the cruise

d = 225 km the distance passed

t = d/v = 225/v the total time of the travel

v*1.5 + (v + 10)(d/v - 1.5 - 0.5) = d (using the formula distance = speed*time)

1.5v + (v + 10)(225/v - 2) = 225

Look at the images to see the solved equation

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Answer:

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Melanie buys a carrying case for her new laptop computer. The retail price is $24.50 and the sales tax is 7%. What is the amount
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4 0
3 years ago
A telephone pole is 24 feet tall. Curtis, who is standing some distance away from the telephone pole measures the angle of eleva
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The distance from the base of the telephone pole to Curtis is about 15 feet.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more number and variables.

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Let d represent the distance from the base of the telephone pole to Curtis, hence:

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The distance from the base of the telephone pole to Curtis is about 15 feet.

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4 0
2 years ago
Anyone mind helping me out?
Igoryamba

Answer:

611 square miles

Step-by-step explanation:

Area of triangle = (1/2)*a*b*sinC (formula when u are not given the height of the triangle, but u are given with the angle.)

= (1/2)*30*47*sin(60°)

= 610.54 square miles (2 d.p)

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:)

4 0
2 years ago
Please help me anybody.
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Answer:

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Step-by-step explanation:

cuz i know

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3 years ago
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