Answer:
hey mate!!
Step-by-step explanation:
x
2
−25=144
X^2=144+25
x^2=169
x=√169
x=13
Sorry mate check out the answer !
Answer:
C, D
Step-by-step explanation:
hope this helped :)
This is the most easier question anyone has asked yet. kill me
Answer:

Step-by-step Explanation:
Given:
∆UVW,
m < U = 33°
m < V = 113°
VW = u = 29 m
Required:
Area of ∆UVW
Solution:
Find side length UV using Law of Sines

U = 33°
u = VW = 29 m
W = 180 - (33+113) = 34°
w = UV = ?

Cross multiply

Divide both sides by sin(33) to make w the subject of formula



(rounded to nearest whole number)
Find the area of ∆UVW using the formula,



(to nearest tenth).