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kiruha [24]
3 years ago
11

Can u make a triangle with 2.1 in., 4 in.,7.9 in.

Mathematics
1 answer:
Alex777 [14]3 years ago
3 0
No, the Triangle Inequality Theorem states that two sides of a triangle always add up to more than the third side. however, 2.1+4 < 7.9. this means that a triangle can't be made
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How to change a subtration problem into a additon problem
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Ex;
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Pls help quick i need this
irina [24]

Answer:

See explanation

Step-by-step explanation:

Q1-5.

1. Plane parallel to WXT is ZYU.

2. Segments parallel to \overline {VU} are \overline {ZY}, \overline {WX} and \overline {ST}

3. Segments parallel to \overline {SW} are \overline {VZ}, \overline {YU} and \overline {XT}

4. Segments skew to \overline {}\overline {XY} are \overline {SV} and \overline {VZ} (not lie in the same plane and not parallel)

5. Segments skew to \overline {}\overline {VZ} are \overline {WX} and \overline {XT} (not lie in the same plane and not parallel)

Q6.

a. \angle 4 and \angle 10 are the same-side interior angles, transversal k

b. \angle 8 and \angle 11 are alternate exterior angles, transversal m

c. \angle 1 and \angle 4 do not form any pair of angles

d. \angle 2 and \angle 12 are the same-side exterior angles, transversal  k

e. \angle 5 and \angle 7 are corresponding angles, transversal  j

f. \angle 2 and \angle 13 are alternate interior angles, transversal l

Q7.

m\angle 1=m\angle 7=131^{\circ} (as vertical angle with angle 7)

m\angle 2=180^{\circ}-131^{\circ}=49^{\circ} (as supplementary angle with angle 1)

m\angle 8=49^{\circ} (as vertical angle with angle 2)

m\angle 3=m\angle 1=131^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 4=m\angle 2=49^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 5=m\angle 7=131^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 6=m\angle 8=49^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 10=m\angle 16=88^{\circ} (as vertical angle with angle 16)

m\angle 9=180^{\circ}-88^{\circ}=92^{\circ} (as supplementary angle with angle 16)

m\angle 15=92^{\circ} (as vertical angle with angle 9)

m\angle 14=m\angle 16=88^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

m\angle 13=m\angle 15=92^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

m\angle 12=m\angle 10=88^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

m\angle 11=m\angle 9=92^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

Q8.

m\angle 7=m\angle 9=105^{\circ} (as vertical angles)

m\angle 8=180^{\circ}-105^{\circ}=75^{\circ} (as supplementary angle with angle 9)

m\angle 10=m\angle 8=75^{\circ} (as vertical angles)

m\angle 6=m\angle 8=75^{\circ} (as alternate interior angles when parallel lines a and b are cut by transversal c)

m\angle 1=180^{\circ}-75^{\circ}-63^{\circ}=42^{\circ} (by angle addition postulate)

m\angle 3=180^{\circ}-42^{\circ}-63^{\circ}=75^{\circ} (by angle addition postulate)

m\angle 4=m\angle 1=42^{\circ} (as vertical angles)

m\angle 5=m\angle 2=63^{\circ} (as vertical angles)

m\angle 11=m\angle 4=42^{\circ} (as alternate interior angles when parallel lines a and b are cut by transversal d)

m\angle 12=180^{\circ}-42^{\circ}=138^{\circ} (as supplementary angles)

m\angle 13=m\angle 11=42^{\circ} (as vertical angles)

m\angle 14=m\angle 12=138^{\circ} (as vertical angles)

3 0
3 years ago
You want to put in a new concrete patio behind your house. You want it to be 12 ft wide by 14 ft long and it needs to be eight i
Ira Lisetskai [31]

Answer:

You will need 187 80 pounds bags of concrete.

Step-by-step explanation:

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2 years ago
What is 16% of 43 minutes? Round answer to tenths place.
sergiy2304 [10]

Answer: 6.9\ minutes

Step-by-step explanation:

Let "x" represents the 16% of 43 minutes.

Once you analize the information given in the exercise, you can identify that 43 minutes is the 100%.

Then, with this data, you can set up the following proportion:

\frac{100}{43}=\frac{16}{x}

Now you must solve for "x". The steps are:

- Multiply both sides of the equation by "x"

 (x)(\frac{100}{43})=(\frac{16}{x})(x)\\\\\frac{100x}{43}=16

- Multiply both sides by 43:

(43)(\frac{100x}{43})=(16)(43)\\\\100x=688

- Divide both sides by 100:

\frac{100x}{100}=\frac{688}{100}\\\\x=6.88

- Rounding to the tenths place:

x\approx6.9

7 0
4 years ago
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