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3 years ago

Y=12/1-n solve for n

Mathematics

1 answer:

Goshia [24]3 years ago

4 0

Answer:

Physics formulas, chemical structures, chemical conversions and reactions. ... solve y' = y^2 x ... prove by induction sum of j from 1 to n = n(n+1)/2 for n>0.

Step-by-step explanation:

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a daily newspaper has 10225 subscribers when it began publication. six years old later it has 8200 subscribers what is the avera

seraphim [82]

Answer:

The rate of change in number of subscriber for the six years is 3.62%

Step-by-step explanation:

Given as :

The initial subscriber of newspaper = p = 10225

The subscriber of newspaper after 6 years of publish = P = 8200

The time period = t = 6 years

Let The average yearly rate of change = r%

<u>Now, According to question</u>

The subscriber of newspaper after n years = initial subscriber × $(1-\dfrac{\textrm rate}{100})^{\textrm time}$

Or, P = p × $(1-\dfrac{\textrm r}{100})^{\textrm t}$

Or, 8200 = 10225 × $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, $\dfrac{8200}{10225}$ = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, 0.80195 = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

<u>Taking power $\dfrac{1}{6}$ both side</u>

So, $(0.80195 )^{\frac{1}{6}}$ = $((1 - \frac{r}{100} )^{6})^{\frac{1}{6}}$

Or, 0.9638 = 1 - $\dfrac{r}{100}$

Or, $\dfrac{r}{100}$ = 1 - 0.9638

Or, $\dfrac{r}{100}$ = 0.0362

Or, r = 0.0362 × 100

i.e r = 3.62

So, The rate of change in subscriber = 3.62%

Hence, The rate of change in number of subscriber for the six years is 3.62% . Answer

4 0

3 years ago

Elizabeth has 1.32 pounds of candy. She wants to share it equally with herself and 3 friends. How much candy will each person re

lana66690 [7]

Answer:

1/3 pound per person

Step-by-step explanation:

(All) (People) (Amount per person)

1.32 / 4 = .33

.33 = 1/3

5 0

3 years ago

Factor 20r+60t to identify the equivalent expression

Nadusha1986 [10]

Answer:

$\boxed{20(r + 3t)}$

Step-by-step explanation:

$20r + 60t$

Factor out 20 from the expression.

$20(r) + 20(3t)$

Take 20 as common.

$20(r + 3t)$

7 0

3 years ago

Find the area of the figure.

seraphim [82]

$\huge \bf༆ Answer ༄$

At first Divide the figure into two rectangles, I and Il

Area of figure l is ~

$\sf24 \times (40 - 30)$

$\sf24 \times 10$

$\sf240 \: \: ft {}^{2}$

Area of figure ll is ~

$\sf 18 \times 30$

$\sf540 \: ft{}^{2}$

Area of whole figure = Area ( l + ll )

that is equal to ~

$\sf240 + 540$

$\sf780 \: \: ft{}^{2}$

7 0

2 years ago

−7y−4x=1 7y−2x=53 Solve the system of equations

Reptile [31]

-7y-4x=17y-2x=53
-4x=24y-2x=53
-2x=24y=53
24y+2x=53

You would have to solve one at a time.
y=53/24
y=2.21
x=53/2
x=26.5

3 0

3 years ago