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SOVA2 [1]
2 years ago
13

The vertices of a triangle are p(3,7) Q(7,-6) R(-8,7). Name the vertices of the image reflected across the x axis

Mathematics
1 answer:
pantera1 [17]2 years ago
6 0

Answer:

<em>P'(3,-7) Q'(7,6) R'(-8,-7).</em>

Step-by-step explanation:

<u>Reflection across the x-axis</u>

Given a point P(x,y), its reflection across the x-axis will map to point P'(x,-y), i.e., the y-coordinate gets inverted.

We are given the vertices of a triangle P(3,7) Q(7,-6) R(-8,7). The vertices of the image reflected across the x-axis are:

P'(3,-7) Q'(7,6) R'(-8,-7).

The new triangle has vertices P'Q'R'.

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matrenka [14]

What do you need help with?

3 0
3 years ago
Read 2 more answers
A phone is 35 percent off which is now worth 78 pounds what was the original price
Black_prince [1.1K]

Answer:

120 pounds

Step-by-step explanation:

65% of y= 78 pounds

\frac{65}{100} × y = 78 pounds

65y = 78  × 100=7800

y= 7800/65= 120 pounds

7 0
3 years ago
I Need help with 4-7
Murrr4er [49]

Answer:

Step-by-step explanation:

4) parallel because 118° is a supplement to 62° and the corresponding angles are both 118°

5) NOT parallel. The labeled angles sum to 120° and would sum to 180° for parallel lines.

6) NOT parallel. see pic.

If parallel, extending a line to intersect ℓ₁ makes an opposite internal angle which would also be 48°. The created triangle would have its third angle at 180 - 90 - 48 = 42° which is opposite a labeled 48° angle, which is false, so the lines cannot be parallel

7)

b = 78°  as it corresponds with a labeled angle above it

a = 180 - 78 = 102° as angles along a line from a common vertex sum to 180

f = is an opposite angle to 180 - 78 - 44 = 58° as angles along a line from a common vertex sum to 180

e = 180 - 90 - 64 = 26° as angles along a line from a common vertex sum to 180

c = 58° as it corresponds with f

d = 180 - 58 = 122° as angles along a line from a common vertex sum to 180

 

4 0
2 years ago
Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.
jek_recluse [69]

Answer:

Choice B: y = 2\, (x - 6)^{2} + 5.

Step-by-step explanation:

For a parabola with vertex (h,\, k), the vertex form equation of that parabola in would be:

\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}.

In this question, the vertex is (6,\, 5), such that h = 6 and k = 5. There would exist a constant a such that the equation of this parabola would be:

y = a\, (x - 6)^{2} + 5.

The next step is to find the value of the constant a.

Given that this parabola includes the point (7,\, 7), x = 7 and y = 7 would need to satisfy the equation of this parabola, y = a\, (x - 6)^{2} + 5.

Substitute these two values into the equation for this parabola:

7 = (7 - 6)^{2}\, a + 5.

Solve this equation for a:

7 = a + 5.

a = 2.

Hence, the equation of this parabola would be:

y = 2\, (x - 6)^{2} + 5.

4 0
3 years ago
Richard cut his pizza into 12 slices. Gianni cut his pizza into 6 slices, and ate 2 slices. Together, ate 9/12 of one pizza. How
andrew11 [14]
FInd the common denominator: 12

That means gianni ate 4/12 of his pizza

Subtract 9/12 by 4/12

You get 5/12



That means 5/12 must be your answer

Richard ate 5/12 of his pizza
Hope this helped
(Answer also can be 5)

8 0
3 years ago
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