The expressions that show different ways to rewrite
are ...
a. (4^x * 4^x) / 4^x
b. 4^x
c. (16 / 4)^x
are ...
a. (4^x * 4^x) / 4^x
b. 4^x
c. (16 / 4)^x
Interval points less than -1
1 answer:
You might be interested in
I think you're factoring this...? You can do that by grouping here. Put the 4 terms in groups of 2 and factor out the greatest common factor. What's left behind is a common binomial factor that can also then be factored out. Like this:
Factoring what we can out of both sets gives us this:
The 2n-5 is a common factor between both the sets of terms, which in turn can also be factored out:
I'm not exactly sure what you are doing with this, but we can keep factoring for the sake of completeness. The 5 n-squared term can also be factored:
and 
and 
so 
. Simplifying that down its simplest is this:
So your three factors for that polynomial are
,
Factoring what we can out of both sets gives us this:
The 2n-5 is a common factor between both the sets of terms, which in turn can also be factored out:
I'm not exactly sure what you are doing with this, but we can keep factoring for the sake of completeness. The 5 n-squared term can also be factored:
So your three factors for that polynomial are