I guess it's B but not sure.
The correct answer is E)52
When there is Hardy-Weinberg equilibrium like in this case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes. Let's put that A is dominant and a is recessive allele. In Hardy-Weinberg equilibrium we have:
p²+2*p*q+q²= 1 p+q=1 p=1-q
f(a) =0.4=q q²=0.4²=0.16=16%
p= 1-0.4=0.6 p²=0.6²=0.36=36%
Percentage of a homozygous genotype in the population is 16%+36%=52%
Well, the food is in the environment. I would like to compare it with how bacteriae feed (however my biology is quite rusty), that is, they engulf their food and they "digest" -- not the proper term, since there are no organs to do real digestion -- it.
Could you add the picture please?
Lions are usually bigger.
