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Romashka [77]
3 years ago
13

A herd of dinosaurs made paintings in the sand with their claws. Each baby dinosaur made 1515 paintings and each adult dinosaur

made 77 paintings. The entire herd made 208208 paintings in total, and there were 33 times as many baby dinosaurs as adult dinosaurs. How many baby dinosaurs and adult dinosaurs were there?
Mathematics
1 answer:
mart [117]3 years ago
8 0

Answer:

4 adult dinosaurs and 12 baby dinosaurs.

Step-by-step explanation:

Let the number of adult dinosaurs be x.

Number of baby dinosaurs = 3x

Number of paintings made by each baby dinosaur = 15

Number of paintings made by each adult dinosaur = 7

Total number of paintings made by 3x baby dinosaurs = Number of baby dinosaurs * Number of paintings made by each baby dinosaur

= 3x * 15

= 45x

Total number of paintings made by x adult dinosaurs = Number of adult dinosaurs * Number of paintings made by each adult dinosaur

= x * 7

= 7x

Total number of paintings made by both baby and adult dinosaurs = 45x + 7x

= 52 x

Again the problem says that the total number of paintings made  = 208

So, 52x = 208

Dividing both sides by 52

\frac{52x}{52}  = \frac{208}{52}

Cancelling out the 52's from the top and bottom on the left

x = 4

So, number of adult dinosaurs = 4

Number of baby dinosaurs = 3x = 3*4 = 12

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Answer:

KL ≈ 1.94

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos48° = \frac{adjacent}{hypotenuse} = \frac{JL}{KL} = \frac{1.3}{KL} ( multiply both sides by KL )

KL × cos48° = 1.3 ( divide both sides by cos48° )

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Answer:

x = y = 104°

Step-by-step explanation:

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max2010maxim [7]

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Step-by-step explanation:

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