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gogolik [260]
3 years ago
12

How would you write this equation in terms of sin and cos as well as simplify it from there?

Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0
Try this option:
(1+ \frac{cosx}{sinx})(1- \frac{cosx}{sinx})- \frac{1}{sin^2x}= \frac{sin^2x-cos^2x}{sin^2x}- \frac{1}{sin^2x}=
= \frac{sin^2x-cos^2x-sin^2x-cos^2x}{sin^2x}=- \frac{2cos^2x}{sin^2x}.
or -2ctg²x
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