How would you write this equation in terms of sin and cos as well as simplify it from there?

1 answer:

8 0

Try this option:
$(1+ \frac{cosx}{sinx})(1- \frac{cosx}{sinx})- \frac{1}{sin^2x}= \frac{sin^2x-cos^2x}{sin^2x}- \frac{1}{sin^2x}=$
$= \frac{sin^2x-cos^2x-sin^2x-cos^2x}{sin^2x}=- \frac{2cos^2x}{sin^2x}.$
or -2ctg²x

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Lyrx [107]

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