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3 years ago

Please help me In this

Mathematics

1 answer:

loris [4]3 years ago

6 0

3 / 12 = 1/4

She puts 1/4 cups of pumpkin seeds on each loaf of bread.

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What’s the answerTo this question?

Inga [223]

X=95 and Y=50.......

7 0

3 years ago

Need help , asap <br> - 50 points

Maksim231197 [3]

Answer:

if you have a calculator then you would have to put it in

8 0

3 years ago

Given a normal distribution with a mean of 128 and a standard deviation of 15, what percentage of values is within the interval

tatyana61 [14]

Answer:

E. 99.7%

Step-by-step explanation:

Calculate each z-score.

z = (x − μ) / σ

z = (173 − 128) / 15

z = 3

z = (x − μ) / σ

z = (83 − 128) / 15

z = -3

You can use a z-score table, or use the empirical rule.

P(-3 < z < 3) = 99.7%.

6 0

3 years ago

A ball is shot from a cannon into the air. The equation that's gives the height (h) of the ball of any time (t) is: h(t)= -16t^2

Gre4nikov [31]

Answer:

26.5 units

Step-by-step explanation:

The height of the ball at any time t is given by :

$h(t)= -16t^2 + 40t + 1.5$ ...(1)

We need to find the maximum height of the ball.

For maximum height, put $\dfrac{dh}{dt}=0$

i.e.

$\dfrac{d( -16t^2 + 40t + 1.5)}{dt}=0\\\\-32t+40=0\\\\t=\dfrac{40}{32}\\\\t=1.25\ s$

Put t = 1.25 in equation (1) to find the maximum height.

So,

$h(t)= -16(1.25)^2 + 40(1.25) + 1.5\\\\=26.5\ units$

So, the maximum height reached by the ball is 26.5 units.

4 0

3 years ago

After a baseball is hit, the height h (in feet) of the ball above the ground t seconds after it is hit can be approximated by th

lubasha [3.4K]

Answer:

The ball will take 4.05 seconds to hit the ground.

Step-by-step explanation:

we have

$h=-16t^{2}+64t+3$

This is a quadratic equation (vertical parabola) open down

The vertex is a maximum

we know that

The ball hit the ground when h=0

Solve the quadratic equation

For h=0

$-16t^{2}+64t+3=0$

The formula to solve a quadratic equation of the form

$at^{2} +bt+c=0$ is equal to

$t=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^{2}+64t+3=0$

$a=-16\\b=64\\c=3$

substitute in the formula

$t=\frac{-64(+/-)\sqrt{64^{2}-4(-16)(3)}} {2(-16)}$

$t=\frac{-64(+/-)\sqrt{4,288}} {-32}$

$t=\frac{64(-)\sqrt{4,288}} {32}=-0.05\ sec$ ---> the time cannot be a negative number

$t=\frac{64(+)\sqrt{4,288}} {32}=4.05\ sec$

therefore

The ball will take 4.05 seconds to hit the ground.

4 0

3 years ago