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weeeeeb [17]
3 years ago
14

What is the decimal expansion for 7 over 9

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
6 0

Answer:

0.77777777......

Step-by-step explanation:

You divide them. Hope I helped!

Please mark Brainliest!!!!

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Bh+hr=25<br> solve for h and r
vova2212 [387]
Take h common:

h(B + r) = 25

Divide b+r
h = 25/ b + r


Subtract bh:

hr = -bh + 25

Divide h:

r = -bh/h + 25/h

Simplify:

r = -b + 25/h

Hope this helps!

5 0
4 years ago
Read 2 more answers
The American Automobile Association reported that families planning to travel over the Labor Day weekend would spend an average
Anuta_ua [19.1K]

Answer:

0.7486 = 74.86% probability of family expenses for the weekend being more than $580.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The American Automobile Association reported that families planning to travel over the Labor Day weekend would spend an average of $735.

This means that \mu = 735

Assume that the amount spent is normally distributed with a standard deviation of $230.

This means that \sigma = 230

What is the probability of family expenses for the weekend being: a. more than $580

This is 1 subtracted by the pvalue of Z when X = 580. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{580 - 735}{230}

Z = -0.67

Z = -0.67 has a pvalue of 0.2514

1 - 0.2514 = 0.7486

0.7486 = 74.86% probability of family expenses for the weekend being more than $580.

5 0
3 years ago
Just write me the equation not that much work
anzhelika [568]
T(2)=d you multiply <em>t</em> times 2 to get <em>d</em>
6 0
4 years ago
Read 2 more answers
The part of the sphere x2 + y2 + z2 = 16 that lies above the cone z = x2 + y2 . (Enter your answer as a comma-separated list of
statuscvo [17]

Answer:

(x,y,z)=(ucos(v), usin(v), \sqrt{16-u^{2})

where 0\leq u\leq 2\sqrt{2} and 0\leq v\leq 2\pi

Step-by-step explanation:

Equation of a cone is z=\sqrt{x^{2} +y^{2}}

Equation of a paraboloid is z=x^{2} +y^{2}

I have parametrised cone here. Please note that equation for cone in the question, is actually a paraboloid.

Imagine a sphere of radius 4, centered at origin and intersecting a cone also centered at origin and height along positive z-axis, given by the equations

x^{2} +y^{2} +z^{2} = 16\\z=\sqrt{x^{2} +y^{2}}

where z\geq x^{2} +y^{2}

Solving for these two equations, and substituting for z in the equation of sphere, we get a circle of radius 2\sqrt{2} units.

The equation of intersecting circle is:

x^{2} +y^{2}=8

Now, according to question, parametrizing this region of circle using parameters u and v.

Consider cylindrical co-ordinates: (r,θ,z)

In cylindrical co-ordinates

(x, y, z)= (r cos(θ),  r sin(θ), z)

x^{2} +y^{2}= r^{2}

Eliminating z, and changing (r, θ)=(u,v)

For cone: x=ucos(v)

y= usin(v)

z=\sqrt{16-u^{2}

or (x,y,z)=(ucos(v), usin(v), \sqrt{16-u^{2})

where 0\leq u\leq 2\sqrt{2} and 0\leq v\leq 2\pi

6 0
3 years ago
Solve for m.<br> 12.6+4m=9.6+8m12.6+4m=9.6+8m
vampirchik [111]

Answer:

m = 3/4

Step-by-step explanation:

12.6+4m=9.6+8m

Isolate the variable, m. Note the equal sign, what you do to one side, you do to the other.

Subtract 4m and 9.6 from both sides:

12.6 (-9.6) + 4m (-4m) = 9.6 (-9.6) + 8m (-4m)

12.6 - 9.6 = 8m - 4m

Simplify:

12.6 - 9.6 = 8m - 4m

3 = 4m

Isolate the variable, m. Divide 4 from both sides:

4m = 3

(4m)/4 = (3)/4

m = 3/4

3/4 is your answer for m.

~

5 0
3 years ago
Read 2 more answers
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