Answer:
Step-by-step explanation:
(x₁, y₁) = (19 , -4) & (x₂ ,y₂) = (17, -20)

![= \frac{-20-[-4]}{17-19}\\\\= \frac{-20+4}{17-19}\\\\= \frac{-16}{-2}\\\\= 8](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B-20-%5B-4%5D%7D%7B17-19%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-20%2B4%7D%7B17-19%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-16%7D%7B-2%7D%5C%5C%5C%5C%3D%208)
m = 8
Parallel lines have same slope.
Parallel slope = 8
Slope of perpendicular line = 
Perpendicular slope = 
Answer:
HI ≈ 12.22
Step-by-step explanation:
tan I = GH / HI
tan 42° = 11 / HI = 0.90
HI = 11/0.90 = 12.22
Given that the sides of the acute triangle are as follows:
21 cm
x cm
2x cm
Stated that 21 cm is one of the shorter sides of the triangle2x is greater than x, so it follows that 2x MUST be the longest side
For acute triangles, the longest side must be less than the sum of the 2 shorter sides
Therefore, 2x < x + 21cm
2x – x < 21cm
x < 21cm
If x < 21cm, then 2x < 42cm
Therefore, the longest possible length for the longest side is 42cm
Answer:
This case has NO solutions.
Step-by-step explanation:
Notice that you are in a case of an obtuse triangle (one of its angles is larger than 90 degrees), the side opposite to the obtuse triangle is shorter than the side adjacent to the angle, so no actual triangle can be formed.
This can be found by simply trying to apply the Law of Sines to solve for the value of angle "B" opposite to side "b":

As shown above, we get an impossible mathematical condition (also call an absurd), since the sine of an angle cannot give a value larger than 1 (one).
Therefore, there is no angle we can find to build a triangle with the given data.
For the first one I got :
V = 165/8
V = B*h
(B)11/2 * (h)15/4
= 165/8
Pls correct me if im wrong!! :)