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Dima020 [189]
2 years ago
10

A: 7,500 miles

Mathematics
1 answer:
kvasek [131]2 years ago
6 0

Answer:

the minimal number is 3

Step-by-step explanation:

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Can you please help me
ioda

Answer: 1/6

Step-by-step explanation:

<u>Given:</u>

4/9 and 11/18

<u>Solve:</u>

<em>STEP ONE: Make the denominators equal by determining the LCM</em>

LCM = Least Common Multiple

First Five multiples of 9 = 9, 18, 27, 36, 45

First FIve multiples of 18 = 18, 36, 54, 72, 90

As we can see from the list above, both 18 and 36 overlap, however, 18 is less than 36. Therefore, 18 is the LCM.

<em>STEP TWO: Compare the size and determine the greater one.</em>

4/9 = (4 × 2) / (9 × 2) = 8/18

11/18 = 11/18

Since 11 > 8, therefore, 11/18 is greater than 8/18

<em>STEP THREE: Find the difference between the two fractions.</em>

 11/18 - 4/9

=11/18 - 8/18

=(11 - 8) / 18

= 3 / 18

= 1/6

Hope this helps!! :)

Please let me know if you have any questions

6 0
3 years ago
Need help!!!!! please need answer
CaHeK987 [17]
=4/3 * 3.14 * 4.8³
=12.56/3 *110.592
=1389.0355/3
=463.01183
ie, 463 cubic inches(approx.)
8 0
2 years ago
If the length of a diagonal of a square is a, what is the length of its side
tankabanditka [31]
The same as the diagonal of a square.
Hope this helped!
8 0
3 years ago
An insurance company has written 52 policies of $50,000, 477 of $25,000, and 918 of $10,000
Ede4ka [16]

The amount of money that the company can expect to pay during the year the policies were written is; $25005

<h3>How to find the expected Value?</h3>

The probability that a person will die at age 20 = 0.001

Revenue from 52 policies = 52 * $75,000 = $3,900,000

Revenue from 477 policies = 477 * $25,000 = $11,925,000

Revenue from 918 policies = 918 * $10,000 = $9,180,000

Total revenue from all policies = $3,900,000 + $11,925,000 + $9,180,000

Total Revenue from all Policies = $25,005,000

Expected amount to pay out during the year the policies were written =  $25,005,000* 0.001 = $25,005

Thus, the company can expect to pay out $45,000 over the year after the policies were written.

Read more about Expected Value at; brainly.com/question/19168423

#SPJ2

8 0
1 year ago
Read 2 more answers
For each of the following vector fields
olga nikolaevna [1]

(A)

\dfrac{\partial f}{\partial x}=-16x+2y

\implies f(x,y)=-8x^2+2xy+g(y)

\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y

\implies\dfrac{\mathrm dg}{\mathrm dy}=10y

\implies g(y)=5y^2+C

\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}

(B)

\dfrac{\partial f}{\partial x}=-8y

\implies f(x,y)=-8xy+g(y)

\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x

\implies \dfrac{\mathrm dg}{\mathrm dy}=x

But we assume g(y) is a function of y alone, so there is not potential function here.

(C)

\dfrac{\partial f}{\partial x}=-8\sin y

\implies f(x,y)=-8x\sin y+g(x,y)

\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y

\implies\dfrac{\mathrm dg}{\mathrm dy}=4y

\implies g(y)=2y^2+C

\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}

For (A) and (C), we have f(0,0)=0, which makes C=0 for both.

4 0
3 years ago
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