Answer:
Option D, telophase
Explanation:
Telophase is the last stage of mitosis cell division in which the duplicated genetic material gets arranged into two identical daughter cells. In generals, this phase begins once the replicated, paired chromosomes have separated and arranged themselves on two opposite sides, or poles of the cells. After this, nuclear envelope begins to form around the chromosomes. After telophase, the cell undergoes cytokinesis to divide the cytoplasm of the parental cell into two daughter cells.
Hence, option D is correct
Answer:
The correct option is option A
Explanation:
Restriction enzymes are endocleases that cleave DNA fragment (<u>of usually four, five or six nucleotide long</u>) at <u>specific sites to produce blunt or sticky ends</u>. They <u>recognize palindromic sequences of host DNA when cleaving the specific sites</u>. The sequences below (on complementary strands) give an example of a palindromic sequences.
5'-CCC║GGG-3'
3'-GGG║CCC-5'
As can be seen above, when read from 5' to 3', the two sequences are the same despite being on opposing strands. And when cut between the guanine (G) and cytosine (C) (as shown above), it produces a blunt end. But when cut as shown below produces a sticky end.
5'- G║AATTC -3'
3'- CTTAA║G -5'
The explanation above shows options C and D are right while option A is wrong (hence the correct option).
Also, bacteria prevent their own DNA from been digested by restriction enzymes by adding methyl group to their restriction sites <u>which prevents restriction enzymes from recognizing restriction sites of their DNA;</u> this generally makes bacterial DNA to be highly methylated. This explanation makes option B right also.
3 position of the molecules.
