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maxonik [38]
3 years ago
14

Calculate5 2/3 -4 5/9

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
7 0

Answer:

17/3 - 41/9

=10/9

Crazy boy [7]3 years ago
6 0
Your answer is 1 1/9

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42 equal W divided by 18
AveGali [126]

42=w/18

x18 to both sides

756=w

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3 years ago
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The circle given by x^2+y^2-6y-12=0 can be written in standard form like this: x^2+(y-k)^2=21 What is the value of k in this equ
sweet [91]

Answer:

The value of k =3

Step-by-step explanation:

x^2+y^2-6y-12=0 We need to solve this equation to become in standard form to find the value of k.

x^2+y^2-6y-12=0\\x^2+y^2-6y = 12\\(x)^2 +(y^2-2(y)(3)+(3)^2) = 12 +(3)^2\\(x)^2+(y-3)^2 = 12+9\\(x)^2 +(y-3)^2 = 21

The given standard form is:

x^2+(y-k)^2=21

Comparing it with (x)^2 +(y-3)^2 = 21

The value of k =3

3 0
3 years ago
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How do you solve this?
motikmotik
Pemdas helps so first you do Parentheses Exponet multiply divide add and subtract
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Write an equation of the line that passes through the given points.<br> (-1,5) and (2, - 7)
Vanyuwa [196]

Answer:

The equation of the straight line is 4x +y = 1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are (-1,5) and ( 2,-7)

Slope of the line

m =\frac{y_{2}-y_{1}  }{x_{2} -x_{1} }  =\frac{-7-5}{2-(-1)}  = \frac{-12}{3} = -4

slope of the line m = -4

<u><em>Step(ii):-</em></u>

The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4

y - y_{1} = m( x-x_{1} )

y - 5 = -4 ( x-(-1))

y -5 = -4 x -4

4 x + y -5 +4=0

4x +y -1 =0

<u><em>Final answer:-</em></u>

The equation of the straight line is 4x +y = 1

<u><em>  </em></u>

6 0
3 years ago
I need help !!!! Please
timofeeve [1]

The answer would be 4.5

6 0
3 years ago
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