Thinking about the graph of f(x), the rate of change is zero whenever there is an extremum.
First, differentiate f(x)
Next, find the zeros of f'(x) by factoring.
Now, we substitute these x-values into the
original equation to find the coordinates.
(-2.667, 11.481), (0, 2)
Hi there
So, if the track is 1/8 of a mile, let's call every lap a "one-eighth mile" run. We know John ran 24 laps, or that he ran 24 "one-eighth miles," just consecutive, one right after another. Let's stop worrying about rates or tricks or math for a second, and just ask: how many real miles is 24 "one-eighth" miles? We know it's less than 24---a lot less, since you have to go around 8 times just to get to 1 mile. Well wait, if we go around 8 times, we get 1 mile. That means if we go around 28, or 16 times, we get 2 miles; And let's just think to the next full mile---if we go 38, or 24 times, we get 3 miles. He did go around 24 times, so he must have run 3 miles on a 1/8 track.
Division and multiplication are inverses of each other. So we solved this by looking for an intuition for how many full miles corresponded to how many laps, with a bunch of steps of multiplication. But you can cut right to the chase and solve it faster with division---24 laps * 1 mile per 8 laps, means:
total distance = 24 Lap (1 mi / 8 Lap) total distance = 24/8 total distance = 3
Answer:
ty for the free points
Step-by-step explanation:
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Answer:
2x-3/y-5/37=0
Step-by-step explanation:
here, given equation of line is
y=3/2x+3
or,y(2x+3)=3
or,2x+3=3/y
or,2x-3/y+3=0...eqn(i)
equation of any line parallel to line (i) is
2x-3/y+k=0.. eqn(ii)
since, the line passes through (4,5)[replacing x=4 and y=5 in eqn(ii), we get]
2*4-3/5+k=0
or,8-3/5+k=0
or,40-3/5+k=0
or,k=-5/37
substituting the value of k=-5/37 in eqn(ii)
2x-3/y-5/37=0 is the required equation of line.
