The graph on the left Fx is the same graph as gx just plus a certain number. You can see from the pictures that they’re similar, just one is shifted down a bit. You can solve to find K by discovering the equation of the graph gx which would be the same as fx and solve for K
Answer:
2,889 digits
Step-by-step explanation:
Total pages of the book = 999 pages
Page 1 - 9 cut separately = 9 digits
Page 10 - 99 = 90 pages
Total digits = 2(90)
= 180 digits cut separately
Page 100 - 999 = 900 pages
Total digits = 3(900)
= 2,700 digits cut separately
how many separate digits does Kai have when he is finished
Total separate digits Kai have when he is finished = 9 digits + 180 digits + 2700 digits
= 2,889 digits
Total separate digits Kai have when he is finished = 2,889 digits
3:5 my answer has to be 20 characters so im just typing the rest of this to answer your question.
Answer: B.
Y = 4x
Step-by-step explanation:
Given that the side of a shape is x
The perimeter of the shape is y
Perimeter of a rectangle can be expressed as:
P = 2L + 2W
Where L = length and W = width
But if the shape is a square, and the side of the shape is x, then, the perimeter will be
P = 4x
Where perimeter P = Y
Therefore, perimeter Y will be;
Y = 4x
Therefore, the correct answer is B which is:
Y = 4x
Answer:
Step-by-step explanation:
1. Null hypothesis: u <= 0.784
Alternative hypothesis: u > 0.784
2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation
Using the formula
sd = √[{P (1-P)}/n]
Where P = 0.84 and n = 750
sd =√[{0.84( 1- 0.84)/750]}
sd=√(0.84 (0.16) /750)
SD =√(0.1344/750)
sd = √0.0001792
sd = 0.013
Then using this we can find z
z = (p - P) / sd
z = (0.84-0.784) / 0.013
z =(0.056/0.013)
z = 4.3077
3. Find the p value and use it to make conclusions...
The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.
4. Conclusions: the results is significant at 0.02 level of significance suck that we can conclude that its on-time arrival rate is now higher than 78.4%.
