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tatuchka [14]
3 years ago
10

What can we do with an exponent when we take the log. Meaning if I do: log5^x what can we do with the x?​

Mathematics
1 answer:
Tamiku [17]3 years ago
7 0

Answer:

You can re write it as an exponential

Step-by-step explanation:

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I need the answer fast
Fantom [35]

Answer:

B. What was the highest temperature this month?

Step-by-step explanation:

Rory is recording the <em>high</em><em>est</em><em> temperature</em> for the duration of the day for month's worth of data.

B. is the easiest one to answer, as you simply will have to look for the greatest number within the set, and that will be the answer.

A. is too broad, and does not imply that only the "high temperature" is needed, rather just a leveled temperature within day in that month.

C. is the opposite of what Rory had recorded, and without data, he cannot answer it.

D. is answerable as well, but, again, the only temperature recorded is the high temperature. Temperature can fluctuate depending on the time of the day, and can be in the 50s one hour and the 90s in another.

~

5 0
3 years ago
If $1400 is the selling price and 10% as the profit percentage. What is the cost price and profit?
xenn [34]

Answer:

1260 is cost price and 140 is profit.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Helpppppppppppppp!!!!!!!!!!!!!!!
Blababa [14]
7/18 because 7 times 1 is 7 and 9 times 2 is 18 :)
7 0
3 years ago
Read 2 more answers
If x+1/x = 5 find the value of x^3 +1/x^3. pls solve​
Korolek [52]

Answer:

1) solve x+1/x = 5

\frac{x + 1}{x}  = 5

x + 1 = 5x

x - 5x =  - 1

- 4x =  - 1

x =  \frac{ -1}{ - 4}

x =  \frac{1}{4}

2) solve x³+1/x³

x {}^{3}  +  \frac{1}{x {}^{3} }

substitute x = 1/4 into the expression

( \frac{1}{4} ) {}^{3}  +  \frac{1}{( \frac{1}{4}) {}^{3}  }

\frac{1}{64}  +  \frac{1}{ \frac{1}{64} }

\frac{1}{64}  +  \frac{64 \times 1}{1}

\frac{1}{64}   + 64

\frac{4097}{64}  \: or \: 64.02

5 0
3 years ago
M=-4/3, point (0,-12)
postnew [5]
Y - y1 = m(x - x1)
slope(m) = -4/3
(0,-12)....x1 = 0 and y1 = -12
sub
y - (-12) = -4/3(x - 0) =
y + 12 = -4/3(x - 0) <=== point slope form

y + 12 = -4/3x 
y = -4/3x - 12 <=== slope intercept form

y = -4/3x - 12
4/3x + y = -12
4x + 3y = -36 <=== standard form
3 0
3 years ago
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