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tatuchka [14]
4 years ago
10

What can we do with an exponent when we take the log. Meaning if I do: log5^x what can we do with the x?​

Mathematics
1 answer:
Tamiku [17]4 years ago
7 0

Answer:

You can re write it as an exponential

Step-by-step explanation:

You might be interested in
Geometry math question no Guessing and Please show work
Len [333]

first lets normalize the equation into y=... form. We can do this by dividing all by 4:

y=(5/4)x - 2

5/4 is the gradient of this line. The perpendicular line will have the negative reciprocal gradient, ie., -4/5, so we're looking for a value of -4/5 in front of the x.

That's only answer B. But it has to go through (-5,4). If you fill in -5, you get -5*-4/5 = +4. So y=(-4/5)x is indeed the correct answer.



3 0
3 years ago
Henry bought a magazine for $5 and two vitamin waters. Henry spent a total of $11. How much did each vitamin water cost?​
marissa [1.9K]

Answer:

$3

Step-by-step explanation:

The magazine=$5 so 3+3 equals 6.

6+5 =11

6 0
3 years ago
Since 1900, the magnitude of earthquakes that measure 0.1 or higher on the Richter Scale in CA are distributed normally with a m
Gwar [14]

Answer:

a) 3.59% probability that a randomly selected earthquake in CA has a magnitude greater than 7.1

b) 1.39% probability that a randomly selected earthquake in CA has a magnitude less than 5.1

c) 73.57% probability that ten randomly selected earthquakes in CA have mean magnitude greater than 6.1

d) 99.92% probability that ten randomly selected earthquakes in CA have mean magnitude between 5.7 and 7.22

e) 6.0735

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 6.2, \sigma = 0.5

a.) What is the probability that a randomly selected earthquake in CA has a magnitude greater than 7.1?

This is 1 subtracted by the pvalue of Z when X = 7.1. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{7.1 - 6.2}{0.5}

Z = 1.8

Z = 1.8 has a pvalue of 0.9641

1 - 0.9641 = 0.0359

3.59% probability that a randomly selected earthquake in CA has a magnitude greater than 7.1

b.) What is the probability that a randomly selected earthquake in CA has a magnitude less than 5.1?

This is the pvalue of Z when X = 5.1. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.1 - 6.2}{0.5}

Z = -2.2

Z = -2.2 has a pvalue of 0.0139

1.39% probability that a randomly selected earthquake in CA has a magnitude less than 5.1

c.) What is the probability that ten randomly selected earthquakes in CA have mean magnitude greater than 6.1?

Now n = 10, s = \frac{0.5}{\sqrt{10}} = 0.1581

This is 1 subtracted by the pvalue of  when X = 6.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{6.1 - 6.2}{0.1581}

Z = -0.63

Z = -0.63 has a pvalue of 0.2643

1 - 0.2643 = 0.7357

73.57% probability that ten randomly selected earthquakes in CA have mean magnitude greater than 6.1

d.) What is the probability that a ten randomly selected earthquakes in CA have mean magnitude between 5.7 and 7.22

This is the pvalue of Z when X = 7.22 subtracted by the pvalue of Z when X = 5.7. So

X = 7.22

Z = \frac{X - \mu}{s}

Z = \frac{7.22 - 6.2}{0.1581}

Z = 6.45

Z = 6.45 has a pvalue of 1

X = 5.7

Z = \frac{X - \mu}{s}

Z = \frac{5.7 - 6.2}{0.1581}

Z = -3.16

Z = -3.16 has a pvalue of 0.0008

1 - 0.0008 = 0.9992

99.92% probability that ten randomly selected earthquakes in CA have mean magnitude between 5.7 and 7.22

e.) Determine the 40th percentile of the magnitude of earthquakes in CA.

This is X when Z has a pvalue of 0.4. So it is X when Z = -0.253.

Z = \frac{X - \mu}{\sigma}

-0.253 = \frac{X - 6.2}{0.5}

X - 6.2 = -0.253*0.5

X = 6.0735

6 0
3 years ago
Solve the inequaliy: (x^2+2)(x−2)^2(6−2x)>0
marin [14]
The answer is x<2
-2x^5 + 14x^4 - 36x^3 + 52x^2 - 64x + 48=0
7 0
4 years ago
Solve for x.
lidiya [134]

Answer:

56

Step-by-step explanation:

3 0
3 years ago
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