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makvit [3.9K]
3 years ago
13

Solve the inequaliy: (x^2+2)(x−2)^2(6−2x)>0

Mathematics
1 answer:
marin [14]3 years ago
7 0
The answer is x<2
-2x^5 + 14x^4 - 36x^3 + 52x^2 - 64x + 48=0
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Suppose a shoe factory produces both low-grade and high-grade shoes. The factory produces at least twice as many low-grade as hi
umka2103 [35]

Answer:

The factory should produce 166 pairs of high-grade shoes and 364 pairs of low-grade shoes for maximum profit

Step-by-step explanation:

The given parameters for the shoe production are;

The number of low grade shoes the factory produces ≥ 2 × The number of high-grade shoes produced by the factory

The maximum number of shoes the factory can produce = 500 pairs of shoes

The number of high-grade shoes the dealer calls for daily ≥ 100 pairs

The profit made per pair of high-grade shoed = Birr 2.00

The profit made per of low-grade shoes = Birr 1.00

Let 'H', represent the number of high grade shoes the factory produces and let 'L' represent he number of low-grade shoes the factory produces, we have;

L ≥ 2·H...(1)

L + H ≤ 500...(2)

H ≥ 100...(3)

Total profit, P = 2·H + L

From inequalities (1) and (2), we have;

3·H ≤ 500

H ≤ 500/3 ≈ 166

The maximum number of high-grade shoes that can be produced, H ≤ 166

Therefore, for maximum profit, the factory should produce the maximum number of high-grade shoe pairs, H = 166 pairs

The number of pairs of low grade shoes the factory should produce, L = 500 - 166 = 334 pairs

The maximum profit, P = 2 × 166 + 1 × 364 = 696

6 1
3 years ago
Read 2 more answers
Put the following equation of a line into slope-intercept form, simplifying all fractions. 5x+6y=42
Sever21 [200]

Answer:

y=-\frac{5}{6} + 7

Step-by-step explanation:

Slope-intercept formula requires us to isolate the y variable. We can do this in just a couple of steps.

1) Move 5x from the left to the right side by subtracting 5x from both sides. This cancels out the 5x on the left side, and remember, what we do to one side we must do to the other to keep the equation balanced.

6y=-5x+42

2) Divide both sides by 6. Again, we are cancelling out the 6 on the left but we must also divide on the right. This would mean dividing -5 and 42 by 6 to get:

y=-\frac{5}{6} + 7

4 0
2 years ago
Which step is the same when constructing an inscribed regular hexagon and an inscribed equilateral triangle?.
Naddik [55]

Step is the same when constructing an inscribed regular hexagon and an inscribed equilateral triangle is shown below:

<h3 /><h3>What is construction?</h3>

Geometric construction is the process of drawing a geometrical figure using two geometrical instruments, a compass, and a ruler.

Construction of an inscribed regular hexagon

1) Set compass width to the radius of the circle

2) Make an arc on the circle with the set radius.

3) From the previous arc draw another arc with the same radius.

4) Continue this process for the other vertex.

5) Connect all the vertices.

Construction of an inscribed equilateral triangle

1) Set compass width to the radius of the circle

2) Make an arc on the circle with the set radius.

3)From the previous arc draw another arc with the same radius.

4)Continue this process for the other vertex.

5) Connect the every other vertices point by drawing  a line between every other adjacent vertex point to form an inscribed equilateral triangle.

Learn more about construction here:

brainly.com/question/791518

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7 0
2 years ago
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
3 years ago
Is 0.25 rational or irrational
love history [14]
0.25 is rational because it is a terminating (means 'its stops') fraction.
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3 years ago
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