Solve the inequaliy: (x^2+2)(x−2)^2(6−2x)>0
1 answer:
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Answer: 545,846,230
Step-by-step explanation: To round 545,846,229 to the nearest ten, we first find the digit in the rounding place which in this case is 2 in the tens place.
Next, look at the digit to the right of the rounding place which in this case is 9. The rules of rounding tell us that if the digit to the right of the rounding place is less than 5, we round down but if the digit to the right of the rounding place is greater than or equal to 5, we round up.
In this problem, since 9 is greater than or equal to 5, we round up. This means we add 1 to the digit in the rounding place so 2 becomes 3 and we change all digits to the right of the rounding place to 0.
Therefore, 545,846,229 rounded to the nearest 10 is 545,846,230.
If we increase q by 2, it means that q becomes q+2.
So, p will become
So, the new value for p is 6 more than the previous one.
The second exercise looks a bit odd: if the sequence started with -100, then it would be
-100, -97, -94, -91, -88,...
And every term would be 3 more than the previous one, so the next term would be -85, but this doesn't appear in your option.
Also, the fact that the sequence starts with positive 100 is quite strange, because it is unrelated to the rest of the sequence.
Are you sure that the exercise is written correct? Or are there any typos?