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4 years ago

Solve the inequaliy: (x^2+2)(x−2)^2(6−2x)>0

Mathematics

1 answer:

marin [14]4 years ago

7 0

The answer is x<2
-2x^5 + 14x^4 - 36x^3 + 52x^2 - 64x + 48=0

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Changing Bases to Evaluate Logarithms in Exercise, use the change-of-base formula and a calculator to evaluate the logarithm. Se

son4ous [18]

Answer:

The question is incomplete, the complete question is "Changing Bases to Evaluate Logarithms in Exercise, use the change-of-base formula and a calculator to evaluate the logarithm. See Example 9. $log_{4}7$ .

$log_{4}7=1.404\\$

Step-by-step explanation:

From the general properties or laws of logarithm, we have the

$log_{a}b=\frac{logb}{loga} \\$

where both log are now express in the natural logarithm base.

i.e $log_{a}b=\frac{lnb}{lna}\\$

hence we can express our $log_{4}7=\frac{ln7}{ln4} \\$ .

the value of ln7 is 1.9459 and ln4 is 1.3863

Hence $log_{4}7=\frac{ln7}{ln4}=\frac{1.9459}{1.3863}\\$ .

$log_{4}7=1.404\\$

6 0

3 years ago

Which term best describes the relationship between the two events described below?

8_murik_8 [283]

maybe C? sorry i’m not the best at this

6 0

2 years ago

Read 2 more answers

1/2 (4 - 2x); 2-2x can some one help

lakkis [162]

Answer:

x=0

Step-by-step explanation:

7 0

3 years ago

What is the product of 1/2 × 2/3 × 3/4 × 4/5

Anastasy [175]

Answer:

5/6

Step-by-step explanation:

brainly pls

6 0

2 years ago

Suppose a normal distribution has a mean of 222 and a standard deviation of 16. What is the probability that a data value is bet

valentina_108 [34]

Mean of the distribution = u = 222
Standard Deviation = s = 16

We have to find the probability that a value lies between 190 and 230.

First we need to convert these data values to z score.

$z= \frac{x-u}{s}$

For x = 190,
$z= \frac{190-222}{16}=-2$

For x = 230
$z= \frac{230-222}{16}=0.5$

So, we have to find the percentage of values lying between z score of -2 and 0.5

P( -2 < z < 0.5) = P(0.5) - P(-2)

From standard z table, we can find and use these values.

P(-2 < x < 0.5 ) = 0.6915 - 0.0228 = 0.6687

Thus, there is 0.6887 probability that the data value will lie between 190 and 230 for the given distribution.

5 0

3 years ago