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makvit [3.9K]
3 years ago
13

Solve the inequaliy: (x^2+2)(x−2)^2(6−2x)>0

Mathematics
1 answer:
marin [14]3 years ago
7 0
The answer is x<2
-2x^5 + 14x^4 - 36x^3 + 52x^2 - 64x + 48=0
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Solve 4/s=-2/9 please help
sergeinik [125]

Answer: 4/15

Step-by-step explanation:

4 0
2 years ago
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A dealer selects a card at random from a standard deck of 52 cards.
Oksanka [162]

Answer:

a) you are correct about a.

b)2/13 chance

c) 1/2 chance

please mark me as brainliest and give me a thanks and five stars please

3 0
3 years ago
Solve the following equation then place the correct number in the box provided. X/3 - 4 = 10
ivann1987 [24]
X = 42

x/3 - 4 = 10
+ 4 +4
x/3 = 14
•3 •3
x = 42
4 0
3 years ago
If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
Dahasolnce [82]

Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα))    (1)

As known cos²α=1-sin²α   (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17   (2)

Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
3 years ago
How many social security numbers are available if the only restriction is that the number 000-00-0000 cannot be assigned?
harkovskaia [24]
Each digit can be 0-9 ( 10 numbers)
 there are 9 numbers in a social security number

multiply 10 nine times:
10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 =  1,000,000,000 ( 1 billion) possibilities.
 
 the restriction is it can't be all zeros so subtract 1 from the total
 1,000,000,000 - 1 = 999,999,999 combinations



3 0
3 years ago
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