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Ivanshal [37]
3 years ago
13

Solve the following equations: 5y/(1 1/3) = y−0.9/0.2

Mathematics
2 answers:
sergejj [24]3 years ago
7 0
The answer is y= -1.63
vazorg [7]3 years ago
6 0

Question: Solve the following equations: 5y/(1 1/3) = y−0.9/0.2

Answer:y= -1 7/11

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Three students earned $48.76 at the bake sell. The students split the earnings evenly, how much did each student recieve?
Sveta_85 [38]

Answer

Find out the  how much did each student recieve .

To prove

Let us assume that  each student earned in the bake sell be x .

As given

Three students earned $48.76 at the bake sell.

The students split the earnings evenly i.e earning is divided into three equal parts .

Than the equation becomes

x = \frac{48.76}{3}

Solving the above

x = $16.25(approx)

Therefore the  each student recieve $16.25(approx) .

Hence proved


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Find the area of a trapezium ABCD in which AB || CD, AB = 14 cm, CD = 8 cm. Given
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Answer:

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Step-by-step explanation:

6 0
2 years ago
1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
2 years ago
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