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3 years ago

Solve the following equations: 5y/(1 1/3) = y−0.9/0.2

Mathematics

2 answers:

sergejj [24]3 years ago

7 0

The answer is y= -1.63

vazorg [7]3 years ago

6 0

Question: Solve the following equations: 5y/(1 1/3) = y−0.9/0.2

Answer:y= -1 7/11

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PLEASE HELP ME PLEASE

ss7ja [257]

A. {2,4,6,8} as the domain is the x values

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2 years ago

a rope is 24 feet long. it is cut into two pieces such that one piece is half the length of the other. find the lengths of the t

Ivahew [28]

Answer:

16 ft and 8 ft

Step-by-step explanation:

x + 1/2 x=24

2/2 x + 1/2 x= 24

3/2 x=24

3 x= 48

x=16

1/2x=16/2=8

3 0

3 years ago

Read 2 more answers

According to a study conducted by the Toronto-based social media analytics firm Sysomos, of all tweets get no reaction. That is,

amm1812

Complete Question

According to a study conducted by the Toronto-based social media analytics firm Sysomos, 75% of all tweets get no reaction. That is, these are tweets that are not replied to or retweeted (Sysomos website, January ). Suppose we randomly select tweets.

a. What is the expected number of these tweets with no reaction (to the nearest whole number)?

b. What are the variance (to 2 decimals) and standard deviation (to 4 decimals) for the number of these tweets with no reaction? Variance Standard deviation

Answer:

The mean is $\mu = 150$

The variance $\sigma^2 =37.5$

The standard deviation is $\sigma \approx 6.1237$

Step-by-step explanation:

A binomial distribution is mathematically represented as $B(n,p)$

where n denotes the number of independent trials =200

And p denote the probability of success = 0.75

We also have the probability of failure which is denoted as q and is equivalent to $1-p$

if p and q are constant then

In binomial distribution the probability of x success and (n-x) is mathematically represented as

$P[X =x] =[\left n} \atop x}} \right. ] p^x (1-p)^{n-x}$

Where x= 0,1,2,...,n $for 0\le p \le 1$

Now $[\left n} \atop x}} \right. ] = \frac{n!}{x(n-x)!}$

Now the mean(Expected number ) of these probability in binomial distribution is mathematically represented as

$\mu = np$

$= 200 *0.75 = 150$

And the variance is mathematically represented as

$\sigma^2 = np(1-p)$

$= 200 * 0.75 (1-0.75) = 37.5$

And the standard deviation is mathematically represented as

$\sigma = \sqrt{np(1-p)}$

$= \sqrt{200 *0.75(1-0.75)} =\sqrt{37.5} \approx 6.1237$

We can obtain the standard z -score of a d

6 0

3 years ago

If you could show as much work as possible that would be amazing!!

Nikitich [7]

Answers:

Reduce:

Here we gave to simplify the expressions:

9) $x^{2}+7x+\frac{12}{x^{2}}+11x+28$

Grouping similar terms:

$(x^{2}+\frac{12}{x^{2}})+(18x+28)$

Applying common factor $x^{2}$ in the first parenthesis and common factor $2$ in the second parenthesis:

$x^{2}(1+\frac{12}{x^{4}})+2(9x+14)$ This is the answer

11) $y^{3}+\frac{27}{y^{2}}+2y-3$

Rearranging the terms:

$(y^{3}+2y)+(\frac{27}{y^{2}}-3)$

Applying common factor $y$ in the first parenthesis and common factor $3$ in the second parenthesis:

$y(y^{2}+2)+3(\frac{9}{y^{2}}-1)$ This is the answer

Multiply:

19) $(\frac{12a^{9}u^{7}}{15 c})(\frac{3c^{4}}{21a^{13 u^{8}}})$

Multiplying both fractions:

$\frac{36 a^{9}u^{7}c^{4}}{315 c a^{13}u^{8}}$

Dividing numerator and denominator by 3 and simplifying:

$\frac{12 c^{3}}{105 c a^{4}u}$ This is the answer

21) $(x-\frac{3}{x}-7)(x^{2}-9x+\frac{35}{x^{2}}-18)$

$(\frac{x^{2}-3-7x}{x})(\frac{x^{4}-9x^{3}+35-18x^{2}}{x^{2}})$

Operating with cross product:

$x^{2} (x^{2}-3-7x) x(x^{4}-9x^{3}+35-18x^{2})$

$x^{9} -9x^{8} -18x^{7}+35x^{5}-7x^{8} +63x^{7}+126x^{6}-245x^{4}-3x^{7}+27x^{6}+54x^{5}-105x^{3}$

Grouping similar terms and factoring:

$x^{9}-2(8x^{8}+21x^{7} )+153x^{6}+89x^{5}-5(49x^{4}+21x^{3})$ This is the answer

Divide:

29) $\frac{\frac{k^{6}}{x^{2}}}{\frac{2k^{4}}{3x^{6}}}$

$\frac{3k^{6}x^{6}}{2x^{2}k^{4}}$

Simplifying:

$\frac{3}{2} k^{2}x^{4}$ This is the answer

33) $\frac{\frac{x+5}{x+1}}{\frac{x^{2}+11x+30}{x^{2}+3x+2}}$

$\frac{(x+5)(x^{2}+3x+2)}{(x+1)(x^{2}+11x+30)}$

Factoring numerator and denominator:

$\frac{(x+5)(x+2)(x+1)}{(x+1)(x+6)(x+5)}$

Simplifying:

$\frac{x+2}{x+6}$ This is the answer

37) $\frac{\frac{x-10}{x+13}}{\frac{x^{3}-1000}{x^{2}+15x+21}}$

$\frac{(x-10)(x^{2}+15x+21)}{(x+13)(x^{3}-1000)}$

Applying the distributive property in numerator and denominator:

$\frac{x^{3}+15x^{2}+21x-10x^{2}-150x-210}{(x+13)(x^{4}-1000x+13x^{3}-13000)}$

Grouping similar terms and factoring by common factor:

$-\frac{5x(x^{2}-129)(x^{2}-42)}{1000x^{3} (x+13)(x-13)}$

Dividing by $5$ in numerator and denominator and simplifying:

$-\frac{(x^{2}-129)(x^{2}-42)}{200x^{2}(x+13)(x-13)}$ This is the answer

3 0

3 years ago

1. The angle of depression from the top of the

STatiana [176]

Answer:

41.7feet

Step-by-step explanation:

From the question we are given the following

angle of depression = 50°

Distance of the pole from the base of the feet = 35feet (Adjacent)

Required

height of the school (opposite)

Using the SOH CAH TOA identity

Tan theta = opp/adj

Tan 50 = H/35

H = 35tan 50

H = 35(1.1918)

H = 41.7feet

Hence the height of the school is 41.7feet

3 0

2 years ago