Ask question

Ask question

All categories

3 years ago

15

11) Identify the range of this set of ordered pairs: {(3,5), (2, 0), (-6, -1), (5, 1)}

1 answer:

Veronika [31]3 years ago

3 0

6

Range is the difference of min and max y values

You might be interested in

Special right triangles.

Oliga [24]

QUESTION 9

The given right angle triangle has its two legs equal to $x\:cm$ and the hypotenuse is $2\:units$ .

Using the Pythagoras theorem, we have

$x^2+x^2=2^2$

This implies that;

$2x^2=2^2$

$2x^2=4$

$x^2=2$

$x=\sqrt{2}$

$x=1.414$

$x\approx1.4\:units$

QUESTION 10

The given right angle triangle has its two legs equal to $x\:units$ and the hypotenuse is $7\:units$ .

Using the Pythagoras theorem, we have

$x^2+x^2=7^2$

This implies that;

$2x^2=7^2$

$2x^2=49$

$x^2=24.5$

$x=\sqrt{24.5}$

$x=4.95\:units$

QUESTION 11

Sam divided the square backyard into two sections along the 40ft diagonal.

Let one of the sides of the garden be $x\:units$ , then the other side of the garden is also $x\:units$ since it was a square backyard.

The diagonal is the hypotenuse which is 40ft and the two legs are $x\:units$ each.

Applying the Pythagoras Theorem, we have;

$x^2+x^2=40^2$

$2x^2=1600$

$x^2=800$

$\Rightarrow x=\sqrt{800}$

$\Rightarrow x=28.28$

The length of one side of the garden is approximately 28cm.

QUESTION 12

The hypotenuse of Nicole's right triangular support is 92cm long.

It was given that the two lengths of the triangular support are of equal length.

Let the two lengths of the triangular support be $l\:cm$ each.

We then apply the Pythagoras theorem to obtain;

$l^2+l^2=92^2$

$\Rightarrow 2l^2=8464$

$\Rightarrow l^2=4232$

$\Rightarrow l=\sqrt{4232}$

$\Rightarrow l=65.05cm$

Therefore Nicole needs $l+l=65.05cm+65.05cm\approx130cm$ of wood to complete the support.

The correct answer is A.

QUESTION 13

A 45-45-90 triangle is an isosceles right triangle.

Let the length of the two legs be $m\:inches$ each.

It was given that the hypotenuse of this triangle is $12\:inches$ .

Applying the Pythagoras Theorem, we have;

$m^2+m^2=12^2$

$\Rightarrow 2m^2=144$

$\Rightarrow m^2=72$

$\Rightarrow m=\sqrt{72}$

$\Rightarrow m=8.49$

The length of one leg of the hypotenuse is approximately 8.5 inches to 1 decimal place.

QUESTIONS 14.

It was given that the distance from home plate to first base is 90 feet.

Since the baseball field form a square, the length of the baselines are all 90ft.

We want to calculate the distance from home plate to 2nd base,which is the diagonal of the square baseball field.

Let this distance be $d\:ft$ , then using the Pythagoras theorem;

$d^2=90^2+90^2$

$d^2=8100+8100$

$d^2=16200$

$\:d=\sqrt{16200}$

$\:d=127.279$

Therefore the distance from home plate to second base is 127 ft to the nearest foot.

QUESTION 15.

The distance from third base to first base is also 127 ft to the nearest foot.

The reason is that the diagonals of a square are equal in length.

3 0

3 years ago

For the function h(x) defined below, find function f(x) and g(x) so that h(x)=(f^ g)(x) . h(x) = ((x + 2)/x) ^ 3

dem82 [27]

Answer:

Step-by-step explanation:

c

4 0

3 years ago

Write 3/5 as a percent. Remember it has to be out of 100 so first make an equivalent fraction with 100 as your bottom number and

sammy [17]

60% as 1/5 is 20% so that times by three is 30%

8 0

3 years ago

Read 2 more answers

Does anybody know the answer to this ?

melisa1 [442]

Answer:

Step-by-step explanation:

5 0

3 years ago

A bag contains 2 red, 4 blue, and 4 yellow marbles. What is the probability of pulling a red marble, putting the marble back, an

Xelga [282]

Answer:

Red: 1/5 or 0.2 or 20% (depends if the question asked you to give the answer in fraction/decimal/percentage. Either way, it's still correct)

Black: 0

Blue: 2/5 or 0.4 or 40%

Step-by-step explanation:

In total, the bag contains 10 balls,

2 are Red = 2/10 = 1/5

There are no black marbles so you have 0 chance of pulling them out.

4 are blue = 4/10 = 2/5

7 0

2 years ago