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pav-90 [236]
3 years ago
5

What is 4v-2(v+4)=-8-3v

Mathematics
1 answer:
andre [41]3 years ago
3 0

Start by distributing:

4v^2 + 16v - 2v - 8

4v^2 + 14v - 8 = -8 - 3v

4v^2 + 14v = 3v

4v^2 + 11v + 0 = 0 (Standard form)


If you are looking for the actual roots:

(-b+-sqrt(b^2-4ac))/2a (Quadratic equation)

where a = 4, b = 11, and c = 0

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Think of -9 as a number 9 to the left of a number line, and then you're adding 11 units, moving -9 11 times to the right. Once you do this, you get 2. Now, adding negative 9 is the same thing as moving 2 9 times to the right. Once you do that as well, you'll get -7. And then just move -7 12 units to the right on the number line and you'll get 5.

Haha that was a really bad explanation, but hope I helped!
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