The triangle ABC is a right angled triangle , right angled at C because it is the angle subtended by the diameter
Now OA = OB = OC = 4 cm (radii)
AB = OA + OB = 8 cm
By pythagoras theorem ,
AC =4
shade region area = area of semicircle - area of triangle
= - 1/2 × base × height
=1/2 × 16 - 1/2 × 4 ×
=8 - 8
=8()
Answer:
INF for first while D for second
Step-by-step explanation:
Ok I think I read that integral with lower limit 1 and upper limit infinity
where the integrand is ln(x)*x^2
integrate(ln(x)*x^2)
=x^3/3 *ln(x)- integrate(x^3/3 *1/x)
Let's simplify
=x^3/3 *ln(x)-integrate(x^2/3)
=x^3/3*ln(x)-1/3*x^3/3
=x^3/3* ln(x)-x^3/9+C
Now apply the limits of integration where z goes to infinity
[z^3/3*ln(z)-z^3/9]-[1^3/3*ln(1)-1^3/9]
[z^3/3*ln(z)-z^3/9]- (1/9)
focuse on the part involving z... for now
z^3/9[ 3ln(z)-1]
Both parts are getting positive large for positive large values of z
So the integral diverges to infinity (INF)
By the integral test... the sum also diverges (D)
Answer:
c
Step-by-step explanation:
hope this help!
have a good day :)
djendsjsjsjejejejejejeh3brvsvw
Third option. They cancel eachother out therefore it'd be 0
Answer:The answer is 26.8.
Step-by-step explanation: