Answer:
A, C, D
Step-by-step explanation:
Consider triangles NKL and NML. These triangles are right triangles, because

In these right triangles:
- reflexive property;
- given
Thus, triangles NKL and NML by HA postulate. Congruent triangles have congruent corresponding parts, so
![\overline{KN}\cong \overline{NM}\\ \\\overline{KL}\cong \overline{LM}\ [\text{option D is true}]](https://tex.z-dn.net/?f=%5Coverline%7BKN%7D%5Ccong%20%5Coverline%7BNM%7D%5C%5C%20%5C%5C%5Coverline%7BKL%7D%5Ccong%20%5Coverline%7BLM%7D%5C%20%5B%5Ctext%7Boption%20D%20is%20true%7D%5D)
Since

then
![7x-4=5x+12\\ \\7x-5x=12+4\\ \\2x=16\\ \\x=8\ [\text{option A is true}]\\ \\MN=KN=7\cdot 8-4=56-4=52\ [\text{option C is true}]](https://tex.z-dn.net/?f=7x-4%3D5x%2B12%5C%5C%20%5C%5C7x-5x%3D12%2B4%5C%5C%20%5C%5C2x%3D16%5C%5C%20%5C%5Cx%3D8%5C%20%5B%5Ctext%7Boption%20A%20is%20true%7D%5D%5C%5C%20%5C%5CMN%3DKN%3D7%5Ccdot%208-4%3D56-4%3D52%5C%20%5B%5Ctext%7Boption%20C%20is%20true%7D%5D)
Option B is false, because KN=52 units.
Option E is false, because LN is congruent KN, not LM
Answer:
Option A.
and 
Step-by-step explanation:
we know that
The solution of the first inequality is the shaded area below the solid line 
The solid line passes through the points (0,4) and (3,0) (the y and x intercepts)
therefore
The first inequality is

The solution of the second inequality is the shaded area to the right of the solid line x=0
therefore
The second inequality is

Answer:
its C
Step-by-step explanation:
because 180⁰-40⁰=140⁰
Ok. So, say you have 1 whole. If you take half of that it would be 50% or 0.50 of the whole. So with 1.34 you can turn it into 1 and 0.34. You have one whole, so that is 100 percent. You than add the 34 hundredths which is 34 percent. So you have 134%. Do you understand all that?
Answer:
Check explanations
Step-by-step explanation:
For all real numbers a,b, and c, the distributive property states that:

For Part A, we have

Or

For Part B, we have
-4(3x-10)+5(2-6x)=-4*3x--4*10+5*2-5*6x
This simplifies to:
-4(3x-10)+5(2-6x)=-12x+40+10-30x
-4(3x-10)+5(2-6x)=-12x-30x+40+10
-4(3x-10)+5(2-6x)=-42x+50
For the C part, we have:



For Part D, we have:

We simplify to get:

Simplify further to get:
