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Mice21 [21]
2 years ago
8

Please help asap! I'll give brainly!

Mathematics
1 answer:
stiks02 [169]2 years ago
3 0

Answer:

for the first one the answer is 75, for the second one its they are not proportional,

Step-by-step explanation:

IM not sure if its correct sorry:)

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How would I find the range btw im only allowed a Ti-84 calculator So pls tell me how to solve this without using any stepbystep
qaws [65]
It’s B, the function is f(x)=20x+4 so you have 7 possible values one at 0 plates 1,2,3,4,5,6 for a total of 7 possible ranges hope that helps
5 0
3 years ago
Read 2 more answers
What is the length of the base of a right triangle with an area of 24 square meters and a height of 4 meters? 3 m 6 m 12 m 96 m
Hunter-Best [27]

Answer: the answer is 12 i took the test

Step-by-step explanation:

6 0
3 years ago
PLZZZ HELPPPP ILL MARK BRAINLIEST TO FIRST AND CORRECT ANSWER THAT HAS WORK AND A THX TO SECOND AND CORRECT ANSWER.
adelina 88 [10]

Answer:

c option

Step-by-step explanation:

Supplementary angles are those which on adding make an angle of 180⁰.

From the the options, only (angle 1 + angle 2) are making an angle of 180⁰.

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>

7 0
2 years ago
How to solve -2(1-7n)-5n=34
OLEGan [10]

-2(1-7n)-5n=34

Multiply the bracket by -2

(-2)(1)=-2

(-2)(-7n)=14n

-2+14n-5n=34

-2+9n=34

Move -2 to the other side. Sign changes from -2 to +2.

-2+2+9n=34+2

9n=34+2

9n=36

Divide by 9 for both sides

9n/9=36/9

n=4

Answer: n=4

6 0
2 years ago
Read 2 more answers
5x - y + z = -6<br> 2x + 7y + 3z = 8<br> x + 2z = 6
BabaBlast [244]

Answer:

Step-by-step explanation:

The system of equations given are:

 

 5x - y + z = -6   ------------- i

 2x + 7y + 3z = 8  ---------- ii

  x + 2z = 6 ----------------- iii

Let us deal with equation i and ii first since they have 3 variables x, y and z;

      5x - y + z = -6                 x 7

       2x + 7y + 3z = 8            x 1

    35x  - 7y + 7z  = -42   ----  iv

      2x  + 7y + 3z  = 8       ---- v

Add equation iv and v;

    37x + 10z  = -34 ------vi

So, let us solve equation vi and iii:

               x + 2z = 6 - ---------- iii   x 10

               37x + 10z  = -34  --- iv  x 2

    10x + 20z   = 60         vi

     74x + 20z  = -68        vii

Subtract vi  - vii;

      -64x  = 128

          x  = -2

So;    put x  = -2 into iii;

           x + 2z  = 6

           -2 + 2z  = 6

            2z  = 6 + 2  = 8

           z  = 4

Put x  = -2 and z = 4 into equation i;

  5(-2) - y + 4  =  - 6

   -10 -y  +4  = -6

       -6  - y  = -6

             -y  = 0

              y  = 0

5 0
3 years ago
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