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tiny-mole [99]
3 years ago
10

Kendra has $ 7.75 $7.75 in nickels and quarters. if she has 13 13 more quarters than nickels, how many of each coin does she hav

e?
Mathematics
1 answer:
Ludmilka [50]3 years ago
7 0
Total of $7.75
13 more quarters than nickels

15 nickels = $0.75
28 quarters = $7.00

28 - 15 = 13 coins
$7.00 + $0.75 = $7.75


She has 15 nickels and 28 quarters.
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Solve using ELIMINATION (with step by step explanation) Please<br><br> 3x+y=-9<br> y=5x+7
Yuki888 [10]

Answer:

<h2>x = -2 (verified by algebra) ✅</h2>

Step-by-step explanation:

Since we are given the value of y, we can replace it with 5x + 7.

We now have: 3x + 5x + 7 = -9

We can now simplify by adding 3x and 5x to get 8x.

8x + 7 = -9

We can subtract 7

8x = -16

And now, we divide by 8

x = -2

We can check to make sure we are correct

3(-2) + 5 (-2) + 7 = -9

-6 + -10 + 7 = -9

-9 = -9 ✅

7 0
3 years ago
Find the area of the trapezoid. points are (-5,-3)(4,-3)(6,-7)(-7,-7)​
Olegator [25]

Answer:

44 square units

Step-by-step explanation:

The area of a trapezoid with bases b₁ and b₂ and height h is given by the formula

A=\left(\dfrac{b_1+b_2}{2}\right)h

If you're wondering how we get this formula, check the attached illustration (remember the area of a parallelogram is its base multiplied by its height)! Moving on to our trapezoid, the pairs of points (-5,-3)(4,-3) and (6,-7)(-7,-7) form two horizontal segments, which form b₁ and b₂, and our height is the distance between the y-coordinates -3 and -7, which is 4. We can find b₁ and b₂ by finding the distance between the x coordinates in their pairs of points:

b_1=|-5-4|=|-9|=9\\b_2=|6-(-7)|=|6+7|=13

Putting it altogether:

A=\left(\dfrac{9+13}{2}\right)(4)=\left(\dfrac{22}{2}\right)(4)=(11)(4)=44

So the area of our trapezoid is 44.

4 0
3 years ago
In ΔLMN, the measure of ∠N=90°, the measure of ∠M=17°, and MN = 20 feet. Find the length of LM to the nearest tenth of a foot.
andrey2020 [161]
20.9 ft
This is a right triangle trigonometry question because N is 90 degrees. MN is adjacent to M and LM is the hypotenuse. Adjacent any hypotenuse use the cosine function. 
cos \theta = \frac{adj}{hyp}
plug in known values
cos(17) = \frac{20}{x}
switch cos(20) and x using the products property
x = \frac{20}{cos(17)}
plug into calculator to get 20.9 ft

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