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3 years ago

Which situation CANNOT be represented by this equation?

1 answer:

4 0

Taliba has $31 to order phone cases online.
Each phone case costs $7, and there is a $4 shipping charge.
How many phone cases, x, can Taliba buy?

^^^ that is the situation that does NOT represent the equation

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What is the constant of variation, k, of the direct variation, y = kx, through (–3, 2)?

UkoKoshka [18]

Y = kx ⇒ k = y/x = 2/(-3) = -2/3

Answer: k = -2/3

8 0

3 years ago

A doctor estimates that a particular patient is losing bone density at a rate of 3% annually. The patient currently has a bone d

kompoz [17]

Answer:

The function f(x) is represented by:

$f(x)=1500(0.97)^x$

Hence, a=1500 and b=0.97

Step-by-step explanation:

The patient currently has a bone density of 1,500 kg/mg^3.

A doctor estimates that a particular patient is losing bone density at a rate of 3% annually.

This means that the bone density that is remaining is:

100-3=97%

which is also represented as: 97%=97/100=0.97

Hence, the function f(x) that represents the bone density after x years is represented by:

$f(x)=a(0.97)^x$

where a is the initial bone density which is given to be: 1500 kg/mg^3.

Hence, the function is:

$f(x)=1500(0.97)^x$

6 0

3 years ago

Read 2 more answers

Cyclists and runners are surveyed about their preferred method for replacing carbohydrates during a long race. The results of th

Novay_Z [31]

Answer:

no its not correct

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the slope for these equations y=-5(2x-3) 10y+6x=-90 12y -4x=-24

AleksAgata [21]

1) 2x 2) 6x 3) -4 There you go

5 0

3 years ago

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Consider a population list x, with a CV= 10%. A second population list, y, has a CV= 20%. The linear regression of y on x is y =

ch4aika [34]

Answer:

The correlation coefficient 0.5 depicts that there is moderate positive correlation between y and x.

Step-by-step explanation:

The linear regression equation is

y= a+bx

The given linear equation is

y= 10x

Here, slope=b=10 and intercept=a=0.

From above equation,

ybar=10xbar

We are given that CVx=0.1 and CVy=0.2

where CV=(standard deviation/mean)*100

We know that

b=r(Sy/Sx)

Multiplying by xbar/ybar on both sides

(xbar/ybar)b=r(Sy/Sx)(xbar/ybar)

(xbar/ybar)b=r[(Sy/ybar)/(Sx/xbar))]

(xbar/ybar)b=r[CVy/CVx]

As CVy/CVx=(Sy/ybar)*100/(Sx/xbar)*100=(Sy/ybar)/(Sx/xbar).

By putting ybar=10xbar, b=10, CVx=0.1 and CVy=0.2.

(xbar/10xbar)10=r(0.2/0.1)

1=r(0.2/0.1)

1=r(2)

r=0.5

There is moderate positive correlation between y and x.

6 0

2 years ago