Answer:
yes
Step-by-step explanation:
I think sorry if I am wrong
I have the same question! have you figured it out ??
Part A.
Ashwin had a 4-cm cube.
volume of cube = side^3
volume = (4 cm)^3 = 64 cm^3
Ashwin has 64 small cubes.
We need to find the volumes of all prisms in Part A. Only prisms with at most 64 cm^3 volume can be the answer.
A. v = 2 * 4 * 7 = 28
B. v = 4 * 5 * 6 = 120
C. v = 5 * 5 * 4 = 100
D. v = 4 * 7 * 5 = 140
E. v = 3 * 5 * 4 = 60
Part A. answer: A, E
Part B.
Dora had a 5-cm cube.
volume of cube = side^3
volume = (5 cm)^3 = 125 cm^3
Dora has 125 small cubes.
We need to find the volumes of all prisms in Part B. Only prisms with at most 125 cm^3 volume can be the answer.
A. v = 3 * 3 * 8 = 72
B. v = 3 * 4 * 5 = 60
C. v = 6 * 6 * 4 = 144
D. v = 5 * 8 * 4 = 160
E. v = 3 * 5 * 4 = 60
Part B. answer: A, B, E
A. It is 176^2 or 30976 or 3.0976 x 10^4 whatever your prefer
B. 972
C. It is 0.00548697 or 4/729 or (2/27)^2 whatever your prefer
D. It is -16 x 20^4 or -2560000 whatever your prefer
E. x^4 y^4
F. h^10 k^6
G. m^11 n^15
H. b^2 d^6
....,,,,,,, you welcome !!!!!! :)
