- Midpoint formula is
.
<h3>19.</h3>
So starting with this one, we will be solving for the coordinates of the unknown endpoint separately. Starting with the x-coordinate, since we know that the midpoint x-coordinate is 5 and the x-coordinate of N is 2, our equation is set up as such: 
From here we can solve for the x-coordinate of Q.
Firstly, multiply both sides by 2: 
Next, subtract both sides by 2 and your x-coordinate is 
With finding the y-coordinate, it's a similar process as with the x-coordinate except that we are using the y-coordinates of the midpoint and endpoint N.
<u>Putting it together, the missing endpoint is (8,4).</u>
<em>(The process is pretty much the same with the other problems, so I'll go through them real quickly.)</em>
<h3>20.</h3>
<u>The missing endpoint is (7,2).</u>
<h3>21.</h3>
<u>The missing endpoint is (-5,1).</u>
Answer:
2. ![\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C0%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
3. ![\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%2621%2660%5C%5C-15%269%26-45%5C%5C%5Cend%7Barray%7D%5Cright%5D)
4. ![\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-14%5C%5C-2%26-6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
2. This matrix is easy, as it just requires addition.
+ ![\left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
3. This matrix requires for the matrices to be multiplied first, then added.
![\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-15%2618%5C%5C-27%2615%26-9%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-12%2636%2642%20%5C%5C12%26%20-6%20%26%20-36%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
4. Here we can add the last 2 matrices to find x.
![\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-8%5C%5C-4%262%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
Hope this helps! (Please consider giving brainliest)
This seems like a personal question
Answer:
<A = 27 degrees
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
Tan A = opp side / adj side
Tan A = 2/4
Tan A = 1/2
Taking the inverse tan of each side
tan^-1 ( tan A) = tan ^-1 (1/2)
A =26.56505118
Rounding to the nearest degree
A = 27
Answer:
Step-by-step explanation:
GIVEN: The weight, in pounds, of a newborn baby 
months after birth can be modeled by the function 
.
TO FIND: What is the y-intercept of the function and what is its interpretation in the context of the problem.
SOLUTION:
in
if 
Hence y-intercept is
the y-intercept in this represents the weight of baby just after he is born.
