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Sergeeva-Olga [200]
3 years ago
12

Please solve this problem... I will mark you brainliest

Mathematics
1 answer:
Blababa [14]3 years ago
8 0
I hope this helps you

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5x+8=9x+12 helpppppp
Marina CMI [18]

Hi there! :)

Answer:

\boxed{X=-1}

<u><em>*THE ANSWER MUST HAVE  A NEGATIVE SIGN!*</em></u>

Step-by-step explanation:

First, you subtract by 8 from both sides of an equation.

5x+8-8=9x+12-8

Subtract.

12-8=4

5x=9x+4

Then, you subtract by 9x from both sides of an equation.

5x-9x=9x+4-9x

Simplify by equation.

-4x=-4

Divide by -4 from both sides of an equation.

-4x/-4=-4/-4

Divide by the numbers from left/right.

-4/-4=-1

\boxed{X=-1}, <em>is the FINAL/CORRECT ANSWER! :)</em>

<em>Have a nice day! :)</em>

<em>:D</em>

<em>-Charlie</em>

<em>Thank you!</em>

4 0
3 years ago
devi bought 7 skirts at x$ each n skirts at 12$ each 2n +1 at 15 each a nd 4 skirts at $3x find the total
nikitadnepr [17]

Answer:

$(19x + 42n + 15)

Step-by-step explanation:

Devi bought 7 skirts at $x each, n skirts at $12 each, (2n + 1) skirts at $15 each and 4 skirts at $3x each. Find the total cost of the skirts she bought.​

total cost of the skirt bought can be determined by adding the  total costs of each shirt bought

7 skirts at $x each = $7x

n skirts at $12 each = $12n

(2n + 1) skirts at $15 = (2n + 1) x 15 = 30n + 15

4 skirts at $3x each = $12x

7x + 12n + 30n + 15 + 12x

combine like terms

19x + 42n + 15

7 0
3 years ago
Which mathematician is not known as a contributor to projective geometry?
gizmo_the_mogwai [7]
<span>Desargues Pythagoras Pappus is the answer i think</span>
7 0
3 years ago
A bus leaves a station traveling north at 70 kilometers per hour. Half an hour later a
Semenov [28]

Answer:

280 km

Step-by-step explanation:

Given that a bus, say b_1, leaves a station traveling north at speed of  70km/hour.

Half an hour later the second bus, say b_2,  leaves a station traveling north at speed of  70km/hour.

As, distance = speed x time,

so, the distance traveled by bus b_1 in 0.5 hours = 70 x 0.5 = 35 km.

Note that, both the buses are traveling in the same direction and when the second bus leaves the station, the first bus already covered a distance of 35 km.

Let the second bus took t hours to meet the first bus and both the buses meet at a distance of d km from the station.

The distance traveled by the first bus from the station, d = 35 + 70t km

\Rightarroe t= \frac {d-35}{70}\cdots(i)

and the distance traveled by the second bus, d = 80t km

\Rightarrow t=\frac {d}{80}\cdots(ii)

Now, equation the equation (i) and (ii), we have

\frac {d-35}{70}=\frac {d}{80} \\\\\Rightarrow 8(d-35)=7d \\\\\Rightarrow 8d - 280 = 7d \\\\\Rightarrow 8d-7d=280 \\\\\Rightarrow d = 280 km

Hence, both the bus will meet at a distance of 280 km from the station.

7 0
3 years ago
What is the answer to this in standard form y+4=2/3(x+7)
Mnenie [13.5K]
Y=2/3x+2/3

I hope this helps!
3 0
4 years ago
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