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Sergeeva-Olga [200]
3 years ago
12

Please solve this problem... I will mark you brainliest

Mathematics
1 answer:
Blababa [14]3 years ago
8 0
I hope this helps you

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The daily budget of $40, to be spent entirely on coffee and comic books. Each comic book is priced at $8 and each
yKpoI14uk [10]

Answer:

3 comic books and 4 cups of coffee

Step-by-step explanation:

8 × 3 = 24

4 × 4 = 16

16 + 24 = 40

6 0
3 years ago
The data below are the frequency of cremation burials found in 17 archaeological sites. a. Obtain the​ mean, median, and mode of
Sergeeva-Olga [200]

Answer:

(a) The mean of the data is 275.

(b) The median of the data is 85.

(c) The mode of the data is 45.

(d)  The measure of center that works best​ here will be median.

Step-by-step explanation:

We are given below the frequency of cremation burials found in 17 archaeological sites. Arranging those in <u>ascending order</u> we get;

28, 31, 32, 45, 45, 47, 59, 67, 85, 86, 143, 256, 272, 390, 424, 524, 2141.

(a) The formula for calculating mean for the above data is given by;

     Mean, \bar X  =  \frac{\sum X}{n}

                =  \frac{28+ 31+ 32+ 45+ 45+ 47+ 59+ 67+ 85+ 86+ 143+ 256+ 272+ 390+ 424+ 524+ 2141}{17}

                =  \frac{4675}{17}  = 275

So, the mean of the data is 275.

(b) Since, the number of observations (n) in our data is odd (i.e. n = 17) , so the formula for calculating median is given by;

                    Median  =  (\frac{n+1}{2} )^{th} \text{ obs.}

                                   =  (\frac{17+1}{2} )^{th} \text{ obs.}

                                   =  (\frac{18}{2} )^{th} \text{ obs.}

                                   =  9^{th} \text{ obs.} = 85

So, the median of the data is 85.

(c) <u>Mode</u> is that value in our data which appears maximum number of times in our data.

So, after observing our data we can see that only number 45 is appearing maximum number of times (2 times) and all other numbers are appearing  only once.

So, the mode of the data is 45.

(d) The measure of center that works best​ here will be median because there are outliers in our data (means extreme values) and mean gets affected by the outliers.

So, the best measure would be median as it represents the middle most value of our data.

4 0
3 years ago
What is the measure of &lt; ABC ??
pav-90 [236]
44 degrees, because an inscribed angle is always half of the arc it intercepts. I hope this helps you!
4 0
4 years ago
Simplify Rewrite the expression in the form 5 ^ n. (5/10)/(5/12) =
Amiraneli [1.4K]

Answer:

5^{-2}

Step-by-step explanation:

5^{(10-12)}

5 0
3 years ago
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