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Elza [17]
3 years ago
14

494 students were surveyed. 58 had a cat. 185 had a dog. 20 had both a cat and a dog.what is the probability that a student had

a cat or a dog
Mathematics
1 answer:
Vesna [10]3 years ago
4 0

Answer:

About 4.05

Step-by-step explanation:


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I think it is -2, if that helps
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In the 2014 - 2015 school year, the mean score on the critical reading of the SAT was 490 with a standard deviation of 102 for j
bonufazy [111]

<u>Answer:</u>

The Ranking Percentile is (B) 97.5%

<u>Explanation :</u>

To find the percentile rank we need to find the z- score. After finding the z-score match this value with the corresponding value in z-score table.

Formula to find the z-score

Z-score=\frac{\text { scored obtained - mean }(\mu)}{\text { standard deviation }(\sigma)}

Substituting the values in the above equation, we find

Z-score= \frac{(694-490)}{102}=2

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Now, the corresponding value of Z-score 2 in the table is 0.9772

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kvv77 [185]
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4 0
3 years ago
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Zolol [24]

Answer:

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Step-by-step explanation:

7*-4=-28

-28*-6=168

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