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Aleks [24]
3 years ago
12

The vertical _____ of a function secant are determined by the points that are not in the domain.

Mathematics
2 answers:
shusha [124]3 years ago
7 0
The vertical asymptotes of a function secant are determined by the points that are not in domain.
Thank you.
luda_lava [24]3 years ago
5 0

Answer:

The vertical <u>asymptote</u> of a function secant are determined by the points that are not in the domain.

Step-by-step explanation:

The domain of a function is the set of x values for which the function is defined.

Secant function is not defined at x=\frac{\pi}{2}+n\pi

It means we cannot include these points in the domain.

At these points, we must have a vertical line which do not touch the graph. These lines are called "Vertical asymptotes"

Vertical asymptotes are not included in the domain of the function.

Hence, the correct word should be "Asymptote"

The vertical <u>asymptote</u> of a function secant are determined by the points that are not in the domain.

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5n + 3d = 420               ..............(i)

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Multiply equation (i)  by 3.

3*(5n + 3d) = 3*(420)

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Equation (ii)  minus (iii)

(12n + 9d) - (15n + 9d) =  1080 - 1260

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3d = 120

d = 120/3 = 40

Therefore Noble fir tree cost $60 while Douglas fir tree cost $40
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