Answer:
11/7 feet
Step-by-step explanation:
the perimeter of a circle is πr²
and a semi circle is half of a circle then the formula would be 1/2 πr²
1/2×22/7×1 (it is 1 because we have divided the diameter to get radius
so we derived at 11/7
Answer: the height in inches, of the pile after 3 weeks is 34 11/12 inches
Step-by-step explanation:
Each consecutive week for the next 5 weeks the height of pile increase by 8 7/12 inches. Converting 8 7/12 inches to improper fraction, it becomes 103/12 inches. The height is increasing in an arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = 17 3/4= 71/4 inches
d = 103/12 inches
n = 3 weeks
the height in inches, of the pile after 3 weeks, T3. Therefore,
T3 = 71/4 + (3 - 1)103/12
T3 = 71/4 + 2 × 103/12 = 71/4 + 103/6
T3 = 419/12 inches = 34 11/12 inches
Answer:
see below
Step-by-step explanation:
The graph opens upward if the sign of the squared term is positive. If that sign is negative, the graph opens downward. The first three equations open upward; the last opens downward.
The line of symmetry is the value of x that makes the squared term zero. Here, that is x=5 for all equations.
<u>y=2/3(x-5)^2</u>: A, D
<u>y=1/2(x-5)^2</u>: A, D
<u>y=3/4(x-5)^2</u>: A, D
<u>y=-4(x-5)^2</u>: B, D
To calculate distance between two points we use the distance formula sqrt((x2−x1)^2+(y2−y1)^2).
To start, we find the square of the distance between x1 and x2 and y1 and y2. The distance between x1 and x2, or 1 and 3, is 2. The distance between y1 and y2, or 3 and -4, is 7.
Now we square 2 and 7 and add them together to get 4 + 49 = 53.
The last thing we do to find the distance is take the square root of 53. 53 is not a perfect square and is also a prime number so our answer in simplest form is still sqrt53.<span />
