3x-2y=6
3(0)-2y=6
0-2y=6
-2y=6
-2y÷-2=6÷-2
y=-3
First one: (0, -3)
3x-2y=6
3(2)-2y=6
6-2y=6
6-6-2y=6-6
-2y=0
-2y÷-2=0÷-2
y=0
Second one: (2,0)
3x-2y=6
3x-2(3)=6
3x-6=6
3x-6+6=6+6
3x=12
3x÷3=12÷3
x=4
Third one: (4,3)
Answer:
2
Step-by-step explanation:
You can divide both of them by 2
Answer: the first one is 14 and the second one is 5
Step-by-step explanation:
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