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borishaifa [10]
3 years ago
12

Give an equality that represents the phrase the sum 1 and y is greater than or equal to 9.

Mathematics
1 answer:
raketka [301]3 years ago
4 0
That would be 1+y≥9

the one and the y go on one side and the nine on the other
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What is 0.467 + 0.025?<br> O A. 0.442<br> B. 0.4695<br> C. 0.492<br> OD. 0.717
enyata [817]

Answer:

C. 0.492

Step-by-step explanation:

All I did was add the two numbers. Add them like normal, even though they are in decimal form. You could also use a calculator. If you don't have one, there should be one programed into your phone and computer.

  0.467

+ 0.025

= 0.492

I hope this helps! Please let me know if you have any more questions or need any more help. Have a great day!

5 0
3 years ago
Suppose both factors in a multiplication problem are multiples of 10. Why might the number of zeroes in the product be different
Lelu [443]

Answer:

Multiplying factors whose products are multiples of 10 add to the number of zeros when factors are multiplied as multiples of 10s.

Step-by-step explanation:

Let the first five multiples of ten be

10*1= 10

10*2= 20

10*3=30

10*4=40

10*5= 50

Suppose we chose 20 and 50.

Now multiplying 20 with 50 we get

20*50= 1000

IF we count the total number of zeros in the factors ( 20 and 50) they are 2.

But the number of zeros in the product (1000) are 3.

This is because when we multiply 2 with 5 we get 10 which adds to the existing number of zeros ( i.e 2) and we get a total of 3 zeros.

And multiplying 10 with 50 we get

10*50= 500

IF we count the total number of zeros in the factors ( 10 and 50) they are 2.

But the number of zeros in the product (500) are also 2.

This is because when we multiply 1 with 5 we get 5 which does not add to the existing number of zeros ( i.e 2) and the total number of zeros remain the same.

Similarly multiplying 20 with 30 we get

20*30= 600

IF we count the total number of zeros in the factors ( 20 and 30) they are 2.

But the number of zeros in the product (600) are also 2.

This is because when we multiply 2 with 3 we get 6 which does not have a zero and the total  number of zeros remain the same as in the factors.

So we see that multiplying factors whose products are multiples of 10 add to the number of zeros when factors are multiplied as multiples of 10s.

5 0
3 years ago
205.2÷5.4<br> I need help
Aloiza [94]
The answer to that question is 38. 
3 0
3 years ago
Read 2 more answers
A grapefruit is 8% heavier than an orange, and an apple is 10% lighter than the orange.
likoan [24]
Weight of an grapefruit=weight of an orange+8% weight of an orange
weight of an apple=weight of an orange -10% weight of an orange

a.<span>By what percentage is the grapefruit heavier than the apple?
We should find the connection between grapefruit and an apple. We know the connection between the weight of a grapefruit and an orange, we know the connection between an orange and an apple, so this means we know the connection between a grapefruit and an apple.
</span>
weight of an grapefruit=weight of an <span>orange+8% weight of an orange
</span>weight of an orange=weight of an apple<span> +10% weight of an apple
</span>
-> weight of an grapefruit=weight of an apple+10% weight of an apple + 8%(weight of an apple+10% weight of an apple)= weight of an apple + 18% weight of an apple + 2% weight of an apple= <span>weight of an apple + 20% weight of an apple 

</span><span>b.By what percentage is the apple lighter than the grapefruit?
</span>weight of an grapefruit=weight of an apple + 20% weight of an apple<span> 
</span>
-> The apple ts 20% lighter than the grapefruit.
8 0
3 years ago
Read 2 more answers
Find the volume of the cone. Use 3.14 for n. Round to the nearest tenth.
enyata [817]

Answer:

1590.6cm {}^{3}

Step-by-step explanation:

volume \: of \: a \: cone \: v =  \frac{1}{3}\pi \: r {}^{2} h \\ radius =  \frac{diameter}{2}  =  \frac{15}{2}  = 7.5 \\ v =  \frac{1}{3}  \times 3.42 \times (7.5) {}^{2} \times 27 \\ v =  \frac{3.142 \times 7.5 \times 7.5 \times 27}{3}    \\ v =  \frac{4771.9125}{3}  = 1590.6375 \\ v = 1590.6cm {}^{3} (approximatly) \\ please \: rate \: and \: mark \: brainliest

7 0
2 years ago
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