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Norma-Jean [14]
3 years ago
11

Write as a product: ac^2–ad+c^3–cd–bc^2+bd

Mathematics
2 answers:
erastovalidia [21]3 years ago
3 0

Answer:

(a+c-b)(c^{2}-d)

Step-by-step explanation:

The given equation is:

ac^{2}-ad+c^{3}-cd-bc^{2}+bd

We have to simplify it and convert to the product form, therefore taking the common terms from the given expression, we get

a(c^{2}-d)+c(c^{2}-d)-b(c^{2}-d)

Now, taking (c^{2}-d) common from all the terms, we get

(a+c-b)(c^{2}-d)

which is the required product form of the given expression.

tatyana61 [14]3 years ago
3 0

Answer:

The product form is (c^2-d)(a+c-b)

Step-by-step explanation:

Given the expression ac^2-ad+c^3-cd-bc^2+bd

we have to write the above expression as a product.

ac^2-ad+c^3-cd-bc^2+bd

Taking a common from first two terms, c from next two and -b from last two terms, we get

a(c^2-d)+c(c^2-d)-b(c^2-d)

Now, taking c^2-d common

⇒ (c^2-d)(a+c-b)

Hence, the product form is (c^2-d)(a+c-b)

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To find the area of the square, you do 7², which is 49 cm². 

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The radius is half the diameter, so it's 7 ÷ 2, which is 3.5 cm.

π3.5² ≈ 38.4845100065 cm².

The shaded region is the area of the square minus the area of the circle.  

49 - 38.4845100065 = <span>10.5154899935, but because you're using 3.14 to approximate pi, the closest answer is 10.54 cm</span>².

The answer is 10.54 cm².
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Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
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faltersainse [42]
Bust out a calculator my dear mammal!
600 +
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;)
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Benni OUT!
8 0
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Gaetano spent $37.80, including tax, on a pair of jeans. How much did the jeans cost if there was an 8% sales tax?
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Now, multiply .08 by 37.80 to get the 8% of 37.80
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</span>



3 0
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