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NeX [460]
3 years ago
10

Martin was given this expression to simplify: 23x + xy – y + 3y + 5 – 20x + 6xy He simplified the expression to: 43x + 7xy −3y W

hat were Martin’s errors? Check all that apply. The combined coefficients of the x terms should be 3x, not 43x. The 7xy should be –7xy. The coefficients of the y terms have been multiplied. When you combine like terms, you add or subtract the coefficients. The constant was left off. The terms xy and 6xy are not like terms because there are two variables.
Mathematics
2 answers:
Debora [2.8K]3 years ago
7 0

Answer:

its a c d

Step-by-step explanation:

got the quiz right on edge

tensa zangetsu [6.8K]3 years ago
3 0

Answer:

Step-by-step explanation:

23x + xy - y + 3y + 5 - 20x + 6xy = 23x - 20x + xy  + 6xy -y + 3y + 5

                                                     = 3x + 7xy + 2y + 5

Errors:1) The combined coefficients of the x terms should be 3x, not 43x

2) The coefficients of the y terms have been multiplied.

3) The constant was left off.

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The equivalent expression is 7^{2}.

We have the following expression -

\frac{7^{-3} }{7^{-5} }

We have to find its equivalent value.

<h3>What is the equivalent expression of the following expression-</h3>

f(x, y) =\frac{A^{x} }{A^{y} }

In order to divide two exponents with same base, we use the 'Quotient property of exponents.

The equivalent expression can be written as -

f(x, y) = A^{x} A^{-y} = A^{x-y}

In the question given we have -

\frac{7^{-3} }{7^{-5} }

Using the property discussed above -

7^{-3}\;7^{5} = 7^{-3+5} = 7^{2}

Hence, the equivalent expression is 7^{2}.

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