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leonid [27]
3 years ago
6

A number has the property that its square is equal to 84 more than five times the number. Enter all numbers that have this prope

rty.
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Answer:

The numbers for which the given property hold true are <em>12 </em>and <em>-7</em>

Step-by-step explanation:

Let the number be x.

As per the given statement:

Square of the number (x^{2}) is 84 more than five times of the number (5x+84).

Writing in the equation form:

x^{2} =5x+84

To find:

All the numbers for which above equation holds true.

Solution:

x^{2} =5x+84

Let us solve the above equation by rearranging the terms and then let us find the roots of the equation.

It is a quadratic equation(i.e. maximum power of x is 2) so it will have 2 solutions  i.e. 2 values of x for which the above equation will hold true.

x^{2} -5x-84=0

Let us factorize the equation.

\Rightarrow x^{2} -12x+7x-84=0\\\Rightarrow x(x -12)+7(x-12)=0\\\Rightarrow (x+7)(x-12)=0\\\Rightarrow \bold{x=12, -7 }

So, the numbers for which the given property hold true are <em>12 </em>and <em>-7</em>.

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Given the figure below, find EF if CA = (6n) and EF = (n + 8)
GalinKa [24]

Answer:

EF = 12

Step-by-step explanation:

Given

CA =6n

EF= n + 8

Required

Find CN

From the attachment:

EF = CD\ and\ CD = DA

Where

CA = CD + DA

This means that:

CA = CD + CD

CA = 2CD

or

CA = 2*EF

This gives:

6n = 2*(n+8)

Open bracket

6n = 2n+16

Collect anf simplify like terms

4n = 16

n= 4

So:

EF= n + 8

EF = 4 + 8

EF = 12

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Step-by-step explanation:

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A

Step-by-step explanation:

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Find the first term and common ratio for the geometric sequence a2 =2.5,a4=62.5
fenix001 [56]

Answer:

a1 = 0.5; common ratio = 5

Step-by-step explanation:

Let the common ratio = r

a2 = 2.5

a3 = 2.5r

a4 = 2.5r * r = 2.5r^2

We are told a4 = 62.5, so

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