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Serga [27]
3 years ago
15

Find the first term and common ratio for the geometric sequence a2 =2.5,a4=62.5

Mathematics
1 answer:
fenix001 [56]3 years ago
6 0

Answer:

a1 = 0.5; common ratio = 5

Step-by-step explanation:

Let the common ratio = r

a2 = 2.5

a3 = 2.5r

a4 = 2.5r * r = 2.5r^2

We are told a4 = 62.5, so

2.5r^2 = 62.5

Divide both sides by 2.5

r^2 = 25

r = 5

a2 = a1 * r

a1 = a2/r = 2.5/5 = 0.5

Answer: a1 = 0.5; common ratio = 5

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Step-by-step explanation:

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you have c and b already. c is the hypotenuse.

a^2 + 16^2 = 20^2

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a^2 = 144

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DiKsa [7]

Answer:

x = 1178 games

Step-by-step explanation:

Let the number of games = x

Let the total cost = Tc

Let the total revenue = Tr

Given the following data;

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Total cost, Tc = (Cost of each game * Number of games) + Investment

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x = \frac {10000}{8.49}

x = 1177.86 ≈ 1178 games.

<em>Therefore, the number of games that must be sold before the business breaks even is 1178 games. </em>

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