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2 years ago

Explain 42+28 by making tens

Mathematics

1 answer:

djverab [1.8K]2 years ago

5 0

Answer:70

Step-by-step explanation:

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como calcular la cantidad de horas por proyecto si un contratista tiene 5,000 horas-hombres y el costo es de $10 y $12 por proye

Tju [1.3M]

Answer:

Each project has 2.500 man-hours

Step-by-step explanation:

Available man hours: 5000

For two projects Costs $

X: project A 10

Y: project B 12

Approach:

X + Y = 5000 => X = 5000 - Y

10 * X + 12 * Y = 55000

replacing:

10 * (5000 - Y) + 12 * Y = 55000

50000 - 10 * Y + 12 * Y = 55000

2 * Y = 55000 - 50000

Y = 5000/2

Y = 2500

For X:

X = 5000 - 2500

X = 2500

The number of hours available for each project are:

Projects Man hours

X: project A 2500

Y: project B 2500

6 0

3 years ago

In the image shown, line n is a transversal cutting parallel lines l and m.

jasenka [17]

Answer:

Its 88

Step-by-step explanation:

6 0

2 years ago

Is -60 greater or least than 60

Lilit [14]

Answer:

less

Step-by-step explanation:

Negatives are less than positives. Have a great day! <3

3 0

2 years ago

Read 2 more answers

4(8x−1) = 19+32x

Fantom [35]

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Answer:

Let's solve your equation step-by-step.

4 ( 8x − 1 ) = 19 + 32x

Step 1: Simplify both sides of the equation.

4 ( 8x − 1 ) = 19 + 32x

( 4 ) ( 8x ) + ( 4 ) ( −1 ) = 19 + 32x ( Distribute )

32x + −4 = 19 + 32x

32x − 4 = 32x + 19

Step 2: Subtract 32x from both sides.

32x − 4 − 32x = 32x + 19 − 32x

−4 = 19

Step 3: Add 4 to both sides.

−4 + 4 = 19 + 4

0 = 23

Answer:

There are no solutions.

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

5 0

2 years ago

Read 2 more answers

Drag each tile to the correct box.

Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

$f(a)=h(3)=4$

$f(b)=h(5)=16$

$a=3$

$b=5$

Substitute

$\frac{16-4}{5-3}=6$

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

$f(a)=f(3)=10$

$f(b)=f(6)=35$

$a=3$

$b=6$

Substitute

$\frac{35-10}{6-3}=8.33$

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

$g(x)=\frac{1}{5}(4)^x$

$f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}$

$f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}$

$a=2$

$b=3$

Substitute

$\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6$

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0

3 years ago