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MAVERICK [17]
3 years ago
14

Zach read a book for 10 minutes every weekend in the first month, 20 minutes in the second month, 40 minutes in the third month,

and 80 minutes in the fourth month. Victoria read a book for 35 minutes every weekend in the first month, 50 minutes in the second month, 65 minutes in the third month, and 80 minutes in the fourth month. Which statement best describes the methods used by Zach and Victoria to increase the time they spent reading a book?
 A: Zach's method is linear because the number of minutes increased by an equal factor every month. B: Victoria's method is linear because the number of minutes increased by an equal number every month. C: Both Victoria's and Zach's methods are exponential because the number of minutes increased by an equal factor every month. D: Both Victoria's and Zach's methods are exponential because the number of minutes increased by an equal number every month.
Mathematics
1 answer:
Wewaii [24]3 years ago
6 0
I do not see an answer, only because Zach's change in reading time increases exponentially, and Victoria's increases at a linear rate.
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44.64/7.44 (per pound cost)= 6

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Okay, cero que es

\frac{4- \sqrt{2} - \sqrt{10} }{4}

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4 years ago
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3 years ago
Gina's literacy bucket weighs 6 pounds. Her novel weighs 1 4/6 pounds, and her chrome book weighs 2 1/6 how much would her bucke
Paraphin [41]

Answer:

2\frac{1}{6} pounds.

Step-by-step explanation:

We have been given that Gina's literacy bucket weighs 6 pounds. Her novel weighs 1 4/6 pounds, and her chrome book weighs 2 1/6.

To find weight of bucket after taking out the two items, we will subtract weight of each item from 6 pounds as:

\text{Weight of bucket}=6-1\frac{4}{6}-2\frac{1}{6}

Let us convert mixed fractions into improper fractions as:

1\frac{4}{6}=\frac{6\cdot 1+4}{6}=\frac{10}{6}\\\\2\frac{1}{6}=\frac{6\cdot 2+1}{6}=\frac{12+1}{6}=\frac{13}{6}

\text{Weight of bucket}=6-\frac{10}{6}-\frac{13}{6}

\text{Weight of bucket}=\frac{6\cdot 6}{6}-\frac{10}{6}-\frac{13}{6}

\text{Weight of bucket}=\frac{36}{6}-\frac{10}{6}-\frac{13}{6}

Combine numerators:

\text{Weight of bucket}=\frac{36-10-13}{6}

\text{Weight of bucket}=\frac{13}{6}

\text{Weight of bucket}=2\frac{1}{6}

Therefore, the weight of the bucket is 2\frac{1}{6} pounds.

6 0
4 years ago
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tatuchka [14]

Answer:

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Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 20

Sample size, n = 13

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

H_{0}: \mu = 20\\H_A: \mu > 20

Formula:

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Now, we calculate the p-value with the help of standard table.

P-value = 0.004

Since, the p-value is less than the significance level, we fail to accept the null hypothesis and reject it.

Thus, there is enough evidence to support that average reflectometer reading for a new type of paint is greater than 20

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