Answer:
The number of expected double crossover progeny is 47.275
To the nearest whole number 47
Step-by-step explanation:
Consider the provided information.
The distance between withered wings (whd) and smooth abdomen (sm) is 30.5,
That means the probability of crossover between them is 0.305.
The distance between smooth abdomen (sm) and speck body (sp) is 15.5,
That means the probability of crossover between them is 0.155
The resulting phenotypically wild-type females were mated with males that had the mutant phenotype for all three traits,
That means the expected frequency of double crossover progeny will be:
0.305×0.155 = 0.047275
It is given that they producing 1000 offspring, therefore,
0.047275×1000 = 47.275
The number of expected double crossover progeny is 47.275
To the nearest whole number 47
