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3 years ago

Please explain how I find the "product" of 21.33 and 2.04?

Mathematics

2 answers:

sashaice [31]3 years ago

7 0

You multiply 21.33 x 2.04

Alenkasestr [34]3 years ago

4 0

A product is when you multiply and get the answer.

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2x squared + 9x=-5 i need to solve for x

In-s [12.5K]

$2x^2+ 9x=-5 \\ \\2x^2 + 9x+5 =0 \\\\a=2, \ \ b=9 , \ \ c=5 \\\\\Delta =b^2-4ac = 9^2 -4\cdot 2\cdot 5 = 81-40=41 \\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-9-\sqrt{41}}{2\cdot 2 }=\frac{-9-\sqrt{41}}{ 4 }\\\\ x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-9+\sqrt{41}}{2\cdot 2 }=\frac{-9+\sqrt{41}}{4 }$

3 0

3 years ago

Kira walks 8 and a half blocks in 17 minutes. If Kira continues to walk at a steady pace, how many blocks will she walk each min

nlexa [21]

Answer:

Half a block ( 0.5 or 1/2 )

Step-by-step explanation:

8 1/2 blocks can also be written as 8.5 blocks.

If Kira walks 8.5 blocks in 17 minutes [and continues to walk at this steady pace], divide 8.5 by 17.

8.5/17 = 0.5

So, Kira walked 0.5 or 1/2 blocks in a minute.

I hope this helps! :)

5 0

2 years ago

What is the sum of the first 30 terms of this arithmetic sequence? 6,13,20,27,34

Galina-37 [17]

Answer:

3135

Step-by-step explanation:

Givens

a1 = 6

Use t4 - t3 to get d

t4 = 27

t3 = 20

Step One

Find a1 and d

a1 = 6

d = t4 - t3

d = 27 - 20

d = 7

Step Two

Find the 30th Term

tn= a1 + (n -1 )*d

t30 = 6 + (30 - 1) * 7

t30 = 6 + 29*7

t30 = 6 + 203

t30 = 209

Step Three

Find the sum using Sum = (a + t30)*n/2

n = 30 given

a1 = 6 given

t30 = 209 calculated from step 2

Sum = (a1 + t30)*n/2 Substitute

Sum = (6+ 209)*30/2 Combine like terms and divide by 2

sum = 215 * 15 Multiply

Sum = 3135 Answer

4 0

3 years ago

If 541 people use the swimming pool and children pay 1.75 dollars and adults pay 2.25 and in total earned was 1041.25 how many c

Zina [86]

Answer:

352 children

Step-by-step explanation:

Solve algebraically using a system of equations

Assign variables

let "a" be the number of adults

let "c" be the number of children <-- We want to find this

a + c = 541 Equation for number of people

2.25a + 1.75c = 1041.25 Equation for money

Rearrange the equation for people. Isolate the variable you don't want to find.

a = 541 - c

Substitute "541 - c", replacing "a", in the equation for money

2.25a + 1.75c = 1041.25

2.25(541 - c) + 1.75c = 1041.25 Distribute over brackets

1217.25 - 2.25c + 1.75c = 1041.25 Collect like terms

1217.25 - 0.5c = 1041.25 Simplified equation

Start isolating "c". Move anything that's not "c" to the right side. Move numbers in reverse BEDMAS order. That means we will add/subtract before dividng/multiplying. When moving a number, do its reverse operation to the entire equation.

1217.25 - 0.5c = 1041.25 Do the reverse of positive 1217.25

1217.25 - 1217.25 - 0.5c = 1041.25 - 1217.25 Subtract 1217.25 on both sides

-0.5c = -176 Do the reverse of multiplying by -0.5

-0.5c/-0.5 = -176/-0.5 Divide both sides by -0.5

c = 352 Number of children

Therefore, there were 352 children in the pool.

5 0

3 years ago

An insurance company sells automobile liability and collision insurance. Let X denote the percentage of liability policies that

qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

$F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100$

#First find $F_x$ and probability distribution function , $f_x(x)$ :

$F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}$

#Have determined the probability distribution unction , $f_x(x)$ , we calculate the Expectation of the random variable X:

$E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200} dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\$

#We then calculate $E(X^2)$ :

$E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28$

Hence, the Var(X) is 764.28

4 0

3 years ago