Ask question

Ask question

All categories

adelina 88 [10]

3 years ago

15

PLEASE ANSWER ASAP!!!!! Rectangle ABCD is dilated to create rectangle A'B'C'D' . The width of rectangle ABCD is 12 feet. The wid

th of rectangle A'B'C'D' is 8 feet. The area of rectangle ABCD is 72 square feet. What is the area of rectangle A'B'C'D' ? square feet

1 answer:

KIM [24]3 years ago

5 0

Answer:

the answer is 72 square feet

Step-by-step explanation:

You might be interested in

The slope i don’t understand rise/run

mel-nik [20]

Answer:

-1

Step-by-step explanation:

The full equation is y= -1x + 2

8 0

3 years ago

A cylindrical oil tank with a radius of 5 meters holds 1,000 cubic meters of oil. What is the approximate height of the tank? Us

antoniya [11.8K]

Hope this helps you.

8 0

3 years ago

Charlotte drives 7.6 miles round trip to work every day. How many miles does she drive to

Morgarella [4.7K]

Answer:

68.4 miles

Step-by-step explanation:

7.6 * 9 = 68.4

8 0

3 years ago

Dad is twice as old as Junior. Gramps is twice as old as Dad. The sum of the three ages is 140. How old is Gramps?

Neporo4naja [7]

Answer:

80

Step-by-step explanation:

We can start of with Junior's age. Then if dad is twice as old as Junior, then we add 2 parts and get 3 parts. Then Gramps is twice as old as Dad so we add 4 parts and get 7 parts. Now we divided 140 by 7. We get 20. This is Junior's age. By looking at that, we know Dad is 40, and Gramps is 80.

Gramps is 80 years old.

6 0

3 years ago

Read 2 more answers

PLEASE HELP<br><br> Identify the radius and center <br><br><br>x^2 +y^2 -6x -2y + 1 = 0

Trava [24]

Answer:

The center is the point (3,1) and the radius is 3 units

Step-by-step explanation:

we know that

The equation of a circle in standard form is equal to

$(x-h)^{2}+(y-k)^{2}=r^{2}$

we have

$x^{2}+y^{2}-6x-2y+1=0$

Convert to standard form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(x^{2}-6x)+(y^{2}-2y)=-1$

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

$(x^{2}-6x+9)+(y^{2}-2y+1)=-1+9+1$

$(x^{2}-6x+9)+(y^{2}-2y+1)=9$

Rewrite as perfect squares

$(x-3)^{2}+(y-1)^{2}=9$

The center is the point (3,1) and the radius is 3 units

4 0

4 years ago