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adelina 88 [10]

3 years ago

15

PLEASE ANSWER ASAP!!!!! Rectangle ABCD is dilated to create rectangle A'B'C'D' . The width of rectangle ABCD is 12 feet. The wid

th of rectangle A'B'C'D' is 8 feet. The area of rectangle ABCD is 72 square feet. What is the area of rectangle A'B'C'D' ? square feet

1 answer:

KIM [24]3 years ago

5 0

Answer:

the answer is 72 square feet

Step-by-step explanation:

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Please help will mark brainliest!!!

11Alexandr11 [23.1K]

Correct answers
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8 0

4 years ago

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How many square feet of carpet will we need for this hole??

vaieri [72.5K]

Bottom = 2x5 = 10ft
Middle = 2x6 ( 4+2) = 12
Top 4x2= 8
10ft+12ft+8ft= 30ft squared

6 0

4 years ago

2(5x+3) ? what is the question

Delicious77 [7]

Hey there!

“2 (5x + 3)”

• FIRST and ONLY STEP: DISTRIBUTE 2 to ALL OF YOUR NUMBERS in the parentheses

2(5x) + 2(3)

2(5x) = 10x ⬅️ FRONT number

2(3) = 6 ⬅️ BACK number

BOTH OF YOUR NUMBERS ARE POSITIVE SO WE DON’T HAVE TO CHANGE ANYTHING

Answer: 10x + 6 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

3 0

3 years ago

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A random sample of n 1 = 249 people who live in a city were selected and 87 identified as a democrat. a random sample of n 2 = 1

kvasek [131]

Answer:

$CI=\{-0.2941,-0.0337\}$

Step-by-step explanation:

Assuming conditions are met, the formula for a confidence interval (CI) for the difference between two population proportions is $\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}$ where $\hat{p}_1$ and $n_1$ are the sample proportion and sample size of the first sample, and $\hat{p}_2$ and $n_2$ are the sample proportion and sample size of the second sample.

We see that $\hat{p}_1=\frac{87}{249}\approx0.3494$ and $\hat{p}_2=\frac{58}{113}\approx0.5133$ . We also know that a 98% confidence level corresponds to a critical value of $z^*=2.33$ , so we can plug these values into the formula to get our desired confidence interval:

$\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\CI=\biggr(\frac{87}{249}-\frac{58}{113}\biggr)\pm 2.33\sqrt{\frac{\frac{87}{249}(1-\frac{87}{249})}{249}+\frac{\frac{58}{113}(1-\frac{58}{113})}{113}}\\\\CI=\{-0.2941,-0.0337\}$

Hence, we are 98% confident that the true difference in the proportion of people that live in a city who identify as a democrat and the proportion of people that live in a rural area who identify as a democrat is contained within the interval {-0.2941,-0.0337}

The 98% confidence interval also suggests that it may be more likely that identified democrats in a rural area have a greater proportion than identified democrats in a city since the differences in the interval are less than 0.

5 0

3 years ago

In the figure, a square is inside another bigger square.

evablogger [386]

Answer:

Part 1) The length of the diagonal of the outside square is 9.9 units

Part 2) The length of the diagonal of the inside square is 7.1 units

Step-by-step explanation:

step 1

Find the length of the outside square

Let

x -----> the length of the outside square

c ----> the length of the inside square

we know that

$x=a+b=4+3=7\ units$

step 2

Find the length of the inside square

Applying the Pythagoras Theorem

$c^{2}= a^{2}+b^{2}$

substitute

$c^{2}= 4^{2}+3^{2}$

$c^{2}=25$

$c=5\ units$

step 3

Find the length of the diagonal of the outside square

To find the diagonal Apply the Pythagoras Theorem

Let

D -----> the length of the diagonal of the outside square

$D^{2}= x^{2}+x^{2}$

$D^{2}= 7^{2}+7^{2}$

$D^{2}=98$

$D=9.9\ units$

step 4

Find the length of the diagonal of the inside square

To find the diagonal Apply the Pythagoras Theorem

Let

d -----> the length of the diagonal of the inside square

$d^{2}= c^{2}+c^{2}$

$d^{2}= 5^{2}+5^{2}$

$d^{2}=50$

$d=7.1\ units$

7 0

3 years ago

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