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Vitek1552 [10]
3 years ago
12

A cylindrical oil tank with a radius of 5 meters holds 1,000 cubic meters of oil. What is the approximate height of the tank? Us

e 3.14 for pi, and round your answer to the nearest meter.
1 meters

13 meters

16 meters

32 meters

Mathematics
1 answer:
antoniya [11.8K]3 years ago
8 0
Hope this helps you.

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Corey flying a kite with 105 meters of string.His string makes an angle of 42 degrees with the level ground. How high is the kit
mafiozo [28]

<u>Given</u>:

Given that Corey is flying a kite with 105 meters of string.

The string makes an angle of 42° with the ground level.

We need to determine the height of the kite.

<u>Height of the kite: </u>

The height of the kite can be determined using the trigonometric ratio.

Thus, we have;

 sin \ \theta=\frac{opp}{hyp}

From the given data, the values are  \theta=42^{\circ}, opp = h (height of the kite) and hyp = 105 meters.

Substituting the values, we get;

sin \ 42=\frac{h}{105}

Multiplying both sides of the equation by 105, we get;

sin \ 42 \times 105=h

0.669 \times 105=h

        70.245=h

Rounding off to the nearest meter, we get;

h=70

Thus, the height of the kite is 70 meters.

8 0
3 years ago
Which value in the set [4, 9, 15, 36] is a solution of 12 = 3 + x?
Travka [436]

Answer:

x=9

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

12=x+3

Step 2: Flip the equation.

x+3=12

Step 3: Subtract 3 from both sides.

x+3−3=12−3

4 0
2 years ago
Read 2 more answers
Find 85% of the number 33.51 help
Makovka662 [10]
33.51 X 85% (0.85) = 28.48
5 0
2 years ago
Read 2 more answers
If the maximum acceleration that is tolerable for passengers in a subway train is 1.74 m/s2 and subway stations are located 930
Free_Kalibri [48]
Given that the subway stations are 930 m apart, the train have to be accerelated for half the distance and then decerelated for the rest of the distance.

Recall that the distance travelled by an object with an initial velocity, u, for a period of time, t, at an accereration, a, is given by
s=ut+ \frac{1}{2} at^2

But, we assume that the train accelerates from rest, thus
s=\frac{1}{2} at^2 \\  \\ \Rightarrow465=\frac{1}{2}(1.74)t^2 \\  \\ \Rightarrow t^2=534.48 \\  \\  \Rightarrow t=\sqrt{534.48}=23.12

The maximum speed is attained at half the center of the distance between subway stations (i.e. at distance = 465 m).

Thus, maximum speed = distance / time = 465 / 23.12 = 20.11 m/s.
6 0
3 years ago
Write the slope-intercept form of the equation that passes through the point (-3, 5) and is perpendicular to the line y = 1/5x +
aleksley [76]

Answer:

<h2>y = -5x - 10</h2>

Step-by-step explanation:

\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\=========================

\text{We have}\ y=\dfrac{1}{5}x+10\to m_1=\dfrac{1}{5}\\\\\text{Therefore}\ m_2=-\dfrac{1}{\frac{1}{5}}=-5.\\\\\text{Put the value of a slope and the coordinates of the point (-3, 5)}\\\text{to the equation}\ y=mx+b:\\\\5=-5(-3)+b\\5=15+b\qquad\text{subtract 15 from both sides}\\-10=b\to b=-10\\\\\text{Finally:}\\\\y=-5x-10

7 0
3 years ago
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